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marysya [2.9K]
2 years ago
10

Please I need help fast

Mathematics
1 answer:
tankabanditka [31]2 years ago
4 0

Answer:

$9.49

Step-by-step explanation:

price after 10% discount:  9.95 x 0.9 = 8.955

price after 6% sales tax: 8.955 x 1.06 = 9.4923

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I need a little help here please
erma4kov [3.2K]

Answer:

Plot points at (0,1) and (-3,3) and draw a line going through both points.

Step-by-step explanation:

Let's start by graphing the y intercept.

y=mx+b

m is the slope. b is the y intercept. Since the equation is y=-2/3x+1, we can conclude the y intercept is 1. We graph a point at (0,1).

If you didn't know the y intercept is where the line intercepts the y-axis.

Now, from the point (0,1) we go up 2 and to the left 3 as it is a negative slope. We reach (-3,3). Plot a point there. Then draw a line going through both points. There's your line!

3 0
2 years ago
3 equivalent ratios for 20/15
castortr0y [4]
4/3
40/30
60/45
Simply multiply or divide both the 20 and the 15 to get an equivalent ratio.
7 0
3 years ago
Read 2 more answers
What is 2+2×2 ? it is little test for your math skills :)​
mr_godi [17]

Answer:

8

Step-by-step explanation:

2+2=4

4*2=8

DONE!!!!!!

8 0
3 years ago
Solve the equation 2x^2 + 4x - 39 to the nearest tenth.
Virty [35]

Answer:

cant be solved, when you try to you get

-1+78 = 77

which is

77 = 77

1=1

So cannot be factored

Step-by-step explanation:

8 0
2 years ago
The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is
podryga [215]

Answer:

(a) 0.408m/sec^2

(b) 0.134m/sec^2

(c) 0.039m/sec^2

Step-by-step explanation:

We have given velocity as function of t v(t)=\frac{85t}{(8t+14)}

Acceleration is equation rate if change of velocity with respect to time

So a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}

(a) Acceleration at t = 5 sec

a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2

(b) Acceleration at t = 10 sec

a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2

(c) Acceleration at t = 20 sec

a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2

5 0
3 years ago
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