Let
x--------> original length side of a square
we know that
area rectangle=length*width
area=126 in²
length=(x+8)
width=(x-3)
so
126=(x+8)*(x-3)------> x²-3x+8x-24=126----> x²+5x-150=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=10 in
the answer isthe original length side of a square is 10 in
Answer:
u = -3
Step-by-step explanation:
Step 1: Write equation
-4 + 2u = -10
Step 2: Solve for <em>u</em>
<u>Add 4 to both sides:</u> 2u = -6
<u>Divide both sides by 2:</u> u = -3
Step 3: Check
<em>Plug in x to verify if it's a solution.</em>
-4 + 2(-3) = -10
-4 - 6 = -10
-10 = -10
Could you add more details to make it more understandable? Your information is bare.
Answer:
a ) 0.1403604645 and 0.1368
b) 0.3464961 and 0.3485
c) 0.802671982 and 0.8018
Step-by-step explanation:
Y~ B (15,0.45)
Y~ N (15*0.45, 15*0.45*0.55) = Y~ N (6.75, 3.7125)
a) P(Y=5) = 15C5 (0.45)^5 * (0.55)^10 = 0.1403604645
For normal approximation
P(Y = 5 ) = P ( 4.5 < Y < 5.5 ) ......... continuity correction
Hence,
The probability P ( 4.5 < Y < 5.5 ) = 0.1368
b) P(Y>7) = 15C8 (0.45)^ 8 (0.55)^7 + 15C9 (0.45)^9 * (0.55)^6 + 15C10 (0.45)^10 * (0.55)^5 + 15C11 (0.45)^11 * (0.55)^4 + 15C12 (0.45)^12 * (0.55)^3 + 15C13 (0.45)^13 * (0.55)^2 + 15C14 (0.45)^14 * (0.55) + (0.45)^15
= 0.3464961
For normal approximation
P(Y > 7 ) = P (Y > 7.5 ) ......... continuity correction
Hence,
The probability P ( Y>7.5 ) = 0.3485
c) P (4 < Y < 10) = 15C5 (0.45)^5 (0.55)^10 + 15C6 (0.45)^ 6 (0.55)^9 + 15C7 (0.45)^7 (0.55)^8 + 15C8 (0.45)^ 8 (0.55)^7 + 15C9 (0.45)^9 * (0.55)^6
= 0.802671982
For normal approximation
P( 4 < Y < 10 ) = P (4.5< Y < 9.5 ) ......... continuity correction
Hence,
The probability P (4.5< Y < 9.5 ) = 0.8018
