All categories

3 years ago

What are all the possible intermolecular forces between acetone and water?.

Chemistry

1 answer:

Ugo [173]3 years ago

3 0

Answer:

Well, the acetone has a dipole, so dipole-dipole forces will be present. Water has a dipole and can also hydrogen bond, as can isobutyl alcohol.

Explanation:

You might be interested in

Give the number of significant figures in this number: 40

lubasha [3.4K]

The # 4 is the only significant # in 400.. Trailing 0's r not significant unless there is a decimal.

in 0.7000, there are 4 significant #'s.

8 0

3 years ago

Read 2 more answers

HELP ME PLEASE WILL MARK BRAINLIEST! DUE AT 8PM TODAY1. What is the unit of measure for the graduated cylinder? What is the maxi

Airida [17]

Answer:

1. Is fortnite travis scott burger

2. Beetlejuice the second

3. The measurement is 69420

Explanation:

my mom told me

7 0

3 years ago

Please help ASAP running late for play offs have no time to do this. Please help , thanks in advance

bagirrra123 [75]

Exo means outer are farthest

thermo means hot or heat

meso means middle or intermediate

tropo means reaction or response

8 0

4 years ago

Where does oxidation and reduction take place in the reaction of Br2 + 2I- → 2Br + I2

Shkiper50 [21]

Okay, let's look at the oxidation number of each substance.
-Br2 has an oxidation number of 0 because it is in a stable form.
- I- has a -1 charge and thus has an oxidation number of -1.
- 2Br- has a -1 charge also
- I2 has an oxidation number of 0 as well.

Bromine goes from 0 to -1 and Iodine goes from -1 to 0.
Therefore, Bromine is having an electron added whilst Iodine is having an electron removed.

Oxidation is Loss of electrons so Iodine is being oxidised, Reduction is Gain of electrons so Bromine is being reduced.

5 0

4 years ago

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide. Calculate the

irakobra [83]

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide. if the original tin sample gained 0.21 g of oxygen, the empirical formula of tin oxide is SnO₂.

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide. if the original tin sample gained 0.21 g of oxygen, the mass of tin oxide is:

$mSn_xO_y = mSn + mO = 0.750 g + 0.21 g = 0.96 g$

Then, we will calculate the mass percent of each element in the oxide.

$\% Sn = \frac{0.750g}{0.96g} \times 100\% = 78\%\\\\\% O = \frac{0.21g}{0.96g} \times 100\% = 22\%$

Next, we will divide each percentage by the atomic mass of the element.

$Sn: 78/118.71 = 0.66\\\\O: 22/16.00 = 1.4$

Finally, we will divide both numbers by the smallest one, i.e. 0.66.

$Sn: 0.66/0.66 = 1\\\\O: 1.4/0.66 \approx 2$

The empirical formula of tin oxide is SnO₂.

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide. if the original tin sample gained 0.21 g of oxygen, the empirical formula of tin oxide is SnO₂.

Learn more: brainly.com/question/1363167

4 0

3 years ago