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bearhunter [10]
3 years ago
14

How many moles are in 390g of silver nitrate

Chemistry
2 answers:
Karolina [17]3 years ago
6 0
There are 2.3 moles (because of significant figures)
katen-ka-za [31]3 years ago
5 0

Answer:

what's 9+10 21 your stuiped no I aint

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Is syrup a compound or solution​
S_A_V [24]

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Syrup is a mixture of thick sticky liquid consisting of a concentrated solution of sugar and water with or without the addition of a flavoring agent or medicinal substance.

Explanation:

so compound

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3 years ago
Question 4 (1 point)
bagirrra123 [75]

Answer:

Argon

Explanation:

The element that would most likely be a good substitute for neon is "argon".

These two elements belong to the noble gases in Group 18(8A) of the Periodic Table. They are inert gases - they do not react chemically with other substances.

Argon, as an inert gas is often used whenever an inert atmosphere is needed. Argon is used in incandescent light bulbs. It is used to stop oxygen from corroding the filament. It is also used by welders to protect weld area.

Argon is a good substitute for neon in this context because they possess some physical properties which are similar.

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3 years ago
An organism contains 28 chromosomes and undergoes asexual reproduction. How many chromosomes will each of the resulting offsprin
Marat540 [252]
Each offspring organism will contain 28 chromosomes
5 0
3 years ago
Please answer, this is due in 30 minutes
notsponge [240]

Answer:

0.591 g of magnesium phosphate is the theoretical yield.

Magnesium nitrate is the limiting reactant.

Explanation:

Hello!

In this case, since the balanced reaction turns out:

3Mg(NO_3)_2+2Na_3PO_4\rightarrow Mg_3(PO_4)_2+6NaNO_3

Next, we compute the grams of magnesium phosphate yielded by each reactant, considering the present mole ratios and molar masses:

m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}=1.00gMg(NO_3)_2*\frac{1molMg(NO_3)_2}{148.31gMg(NO_3)_2}*\frac{1molMg_3(PO_4)_2}{3molMg(NO_3)_2}  *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Mg(NO_3)_2}= 0.591gMg_3(PO_4)_2\\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4}=1.00gNa_3PO_4*\frac{1molNa_3PO_4}{163.94gNa_3PO_4}*\frac{1molMg_3(PO_4)_2}{2molNa_3PO_4}  *\frac{262.86gMg_3(PO_4)_2}{1molMg_3(PO_4)_2} \\\\m_{Mg_3(PO_4)_2}^{by\ Na_3PO_4} = 0.802gMg_3(PO_4)_2

Thus, we infer that the correct theoretical yielded mass is 0.591 g as magnesium nitrate is the limiting reactant for which it produces the fewest grams of product.

However, is not possible to compute the percent yield since no actual yield is given, and must be provided or indicated by the problem or an experiment and it not here, nevertheless, you may compute the percent yield by dividing the actual yield by the theoretical and then multiplying by 100:

Y=\frac{actual}{0.591g}*100\%

Best regards!

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3 years ago
Write about discovery of penicillin​
Rzqust [24]

Answer:

The Scottish physician Alexander Fleming was the first to suggest that a Penicillium mould must secrete an antibacterial substance, and the first to concentrate the active substance involved, which he named penicillin, the first modern antibiotic, in 1928.

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