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Triss [41]
3 years ago
14

If you have 0.5 L of air in a rigid, sealed container at a pressure of 203 kPA and a temp of 203. You heat the contain to 273 K.

What is the final pressure of the air?
151 kPA
102 kPA
273 kPA
310 kPA
Chemistry
1 answer:
Dima020 [189]3 years ago
6 0
Volume remains constant: P1 x T2 = P2 x T1. Pressure increases in direct proportion to absolute temperature increase. 
<span>203kPa x 273K = P2 x 203K = P2 x 55,419. </span>
<span>P2 = 55,419 / 203 =   273kPa final pressure. </span>
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