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antiseptic1488 [7]
3 years ago
6

Solve for y. y/m + y/n = p

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0
<h3>Given :</h3>

\boxed{ \rm  \frac{y}{m} +  \frac{y}{n}  = p}

\\  \\

<h3>To find:</h3>

\\

  • Value of y

\\  \\

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{y}{m} +  \dfrac{y}{n}  = p

write the equation

\\  \\

\dashrightarrow \sf \dfrac{\frac{y \times mn}{m} +  \frac{y \times mn}{n}}{mn}  = p

Add y/n with y/n and we will get Lcm as mn

\\  \\

\dashrightarrow \sf \dfrac{\frac{y \times  \cancel mn}{\cancel m} +  \frac{y \times m\cancel n}{\cancel n}}{mn}  = p

Cancel the similar terms

\\  \\

\dashrightarrow \sf \dfrac{\frac{y \times  n}{1} +  \frac{y \times m}{1}}{mn}  = p

\\  \\

\dashrightarrow \sf \dfrac{yn + ym}{mn}  = p

remove 1 as denominator

\\  \\

\dashrightarrow \sf \dfrac{y(n + m)}{mn}  = p

take y as common

\\  \\

\dashrightarrow \sf \dfrac{(n + m)}{mn}  =  \dfrac{p}{y}

transfer y to other side as denominator of p

\\  \\

\dashrightarrow \sf \dfrac{mn}{(n + m)}  =  \dfrac{y}{p}

reciprocal the whole equation

\\  \\

\dashrightarrow \sf \dfrac{mnp}{(n + m)}  =  \dfrac{y}{1}

transfer p other side as numerator

\\  \\

\dashrightarrow \boxed{ \bf y = \dfrac{mnp}{(n + m)} }

\\  \\

\therefore \red {\underline {\textbf{\textsf{Option 2 i.e \{y= mnp/(m+n) \} is correct }}}}

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A coconut cream pie recipe uses 6 ounces of crearn cheese, 12 ounces of condensed milk, and 10 ounces whipped topping In simples
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Answer:

1 oz of cream cheese to every 2 oz of condensed milk

Step-by-step explanation:

We can completely disregard whipped topping because it does not ask for it.

We have 6 ounces of cream cheese to 12 ounces of condense milk. We can write this as a ration:

6:12

6 oz cream cheese:12 oz condensed milk

The question is basically asking to simplify 6:12

Since the greatest commond factor is 6, we can divide both sides by 6 and get:

1:2

Therefore, there is 1 oz of cream cheese to every 2 oz of condensed milk

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Which equation can be used to solve for the value of n if 2 + n = 12?
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A new process of more accurately detecting anaerobic respiration in cells is being tested. The new process is important due to i
almond37 [142]

Answer:

a) 0.97605 = 97.605% probability that the process will signal.

b) 0.2076 = 20.76% probability that microaerophiles are present.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability that the process will signal?

It signals in these following moments:

97.8% of 31%(contains obligate anaerobes).

98.1% of 27%(contains facultative anaerobes).

96.5% of 21%(contains microaerophiles).

99.2% of 12%(contains nanaerobes).

95.9% of 9%(contains aerotolerant). So

p = 0.978*0.31 + 0.981*0.27 + 0.965*0.21 + 0.992*0.12 + 0.959*0.09 = 0.97605

0.97605 = 97.605% probability that the process will signal.

b. If the test signals, what is the probability thatmicroaerophiles are present?

Event A: Test signals

Event B: Contains microaerophiles

0.97605 = 97.605% probability that the process will signal.

This means that P(A) = 0.97605

Intersection of events A and B:

Signals containing microaerophiles, which is 96.5% of 21%. So

P(A \cap B) = 0.965*0.21 = 0.20265

The probability that microaerophiles are present is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.20265}{0.97605} = 0.2076

0.2076 = 20.76% probability that microaerophiles are present.

3 0
3 years ago
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