All categories

3 years ago

What are some things about the relationship of the circumference and the diameter of a circle?

1 answer:

6 0

The most notable relationship is that you can find the circumference of a circle with a diameter. Multiply the diameter times pi, and you will find your circumference.

You can also divide your circumference by pi to find your diameter.

You might be interested in

A school earns $70 from selling 50 tickets for the school play. Each ticket costs the same amount . How much dose the school ear

ivann1987 [24]

1.40$ you simply divide 70/50

6 0

2 years ago

John made 12 dollars per delivery plus a base pay of 30 dollars. If he made 150 dollars, how

Tasya [4]

Answer:

he did 10 delivery

Step-by-step explanation:

if john gets 12 per delivery and gets 30 base pay that means

150-30=120

120/12=10

6 0

3 years ago

What type of triangle center is shown as point C in the figure?

nika2105 [10]

Answer:

Step-by-step explanation:

notice the circle around the triangle

4 0

2 years ago

One type of insect is 0.0052 meters long. what is this length in scientific notation?

pochemuha

Your answer would be:
5.2*10^(-3)

hope this helps!
happy thanksgiving

4 0

3 years ago

Read 2 more answers

For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

mihalych1998 [28]

Answer:

$V=196in^3$

Step-by-step explanation:

The volume of a pyramid is:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

$A_{b}=l^2$

where $l$ is the length of the side: $l=8in$ , thus:

$A_{b}=(8in)^2\\A_{b}=64in^2$

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

$hypotenuse^2=leg1^2+leg2^2$