Question

. A 225-kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate

Answer 1

The acceleration of the crate is 1.196 m/s².

What is acceleration?

This can be defined as the rate of change of velocity.

To calculate the acceleration of the crate, we use the formula below.

Formula:

• a = (F-mgμ)/m................. Equation 1

Where:

• a = acceleration of the crate
• m = mass of the crate

• F = Force applied to the crate
• μ = Coefficient of friction

From the question,

Given:

• m = 225 kg
• F = 710 N
• g = 9.8 m/s²
• μ = 0.20

Substitute the values above into equation 1

• a = [710-(225×9.8×0.20)]/225
• a = (710-441)/225
• a = 269/225
• a = 1.196 m/s²

Hence, The acceleration of the crate is 1.196 m/s²

Learn more about acceleration here: brainly.com/question/460763