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bixtya [17]
1 year ago
7

a piston has an external pressure of 8.00 atmatm . how much work has been done in joules if the cylinder goes from a volume of 0

.160 liters to 0.490 liters?
Physics
1 answer:
Naya [18.7K]1 year ago
4 0

The work done by the gas is 267 J.

<h3>What is the work done?</h3>

To obtain the work done by a gas, we have to consider the initial and the find pressure or in other words, the change in the volume of the system.

Thus we know that;

W = PΔV

W = wok done

P = pressure

V = volume

W = 8.00 atm(0.490 liters - 0.160 liters)

W =2.64 atmL

1 L atm = 101 J

2.64 atmL = 2.64 atmL *  101 J/1 L atm

= 267 J

Learn more about work done by a gas:brainly.com/question/12539457

#SPJ4

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Yakvenalex [24]

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Gravity is dependent on the mass of two bodies and the distance between them. There is a strong gravitational attraction between Earth and the Moon because they’re relatively close to one another. There is a strong gravitational attraction between Earth and the Sun because the Sun is so massive

7 0
2 years ago
How much heat is needed to bring 12.0 g of water from 28.3 °C to 43.87 °C, if the specific heat capacity of water is 4.184 J/(g•
Vika [28.1K]

Answer:

Heat capacity, Q = 781.74 Joules

Explanation:

Given the following data;

Mass = 12g

Initial temperature = 28.3°C

Final temperature = 43.87°C

Specific heat capacity of water = 4.184J/g°C

To find the quantity of heat needed?

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 43.87 - 28.3

dt = 15.57°C

Substituting into the equation, we have;

Q = 12*4.184*15.57

Q = 781.74 Joules

7 0
3 years ago
a 75 kg man is standing at rest on ice while holding a 4kg ball. if the man throws the ball at a velocity of 3.50 m/s forward, w
AysviL [449]

Answer:

His resulting velocity will be 0.187 m/s backwards.

Explanation:

Given:

Mass of the man is, M=75\ kg

Mass of the ball is, m=4\ kg

Initial velocity of the man is, u_m=0\ m/s(rest)

Initial velocity of the ball is, u_b=0\ m/s(rest)

Final velocity of the ball is, v_b=3.50\ m/s

Final velocity of the man is, v_m=?\ m/s

In order to solve this problem, we apply law of conservation of momentum.

It states that sum of initial momentum is equal to the sum of final momentum.

Momentum is the product of mass and velocity.

Initial momentum = Initial momentum of man and ball

Initial momentum = Mu_m+mu_b=75\times 0+4\times 0 =0\ Nm

Final momentum = Final momentum of man and ball

Final momentum = Mv_m+mv_b=75\times v_m+4\times 3.50 =75v_m+14

Now, initial momentum = final momentum

0=75v_m+14\\\\75v_m=-14\\\\v_m=\frac{-14}{75}\\\\v_m=-0.187\ m/s

The negative sign implies backward motion of the man.

Therefore, his resulting velocity is 0.187 m/s backwards.

3 0
3 years ago
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ICE Princess25 [194]

Answer:

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