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bixtya [17]
1 year ago
7

a piston has an external pressure of 8.00 atmatm . how much work has been done in joules if the cylinder goes from a volume of 0

.160 liters to 0.490 liters?
Physics
1 answer:
Naya [18.7K]1 year ago
4 0

The work done by the gas is 267 J.

<h3>What is the work done?</h3>

To obtain the work done by a gas, we have to consider the initial and the find pressure or in other words, the change in the volume of the system.

Thus we know that;

W = PΔV

W = wok done

P = pressure

V = volume

W = 8.00 atm(0.490 liters - 0.160 liters)

W =2.64 atmL

1 L atm = 101 J

2.64 atmL = 2.64 atmL *  101 J/1 L atm

= 267 J

Learn more about work done by a gas:brainly.com/question/12539457

#SPJ4

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Neko [114]

Answer:

58.8J

Explanation:

Given parameters;

Mass of ball  = 4kg

Height above the floor  = 1.5m

g  = 9.8n/kg

Unknown:

Potential energy  = ?

Solution:

The potential energy of a body is the energy due to the position of the body.

It is mathematically expressed as:

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3 years ago
A parallel-plate air capacitor is made from two plates 0.210 m square, spaced 0.815 cm apart. it is connected to a 120 v battery
GuDViN [60]

Answer:

at the beginning: 2.3\cdot 10^{-10} F

when the plates are pulled apart: 1.1\cdot 10^{-10} F

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=k \epsilon_0 \frac{A}{d}

where

k is the relative permittivity of the medium (for air, k=1, so we can omit it)

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the permittivity of free space

A is the area of the plates of the capacitor

d is the separation between the plates

In this problem, we have:

A=0.210 m^2 is the area of the plates

d=0.815 cm=8.15\cdot 10^{-3} m is the separation between the plates at the beginning

Substituting into the formula, we find

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{8.15\cdot 10^{-3} m}=2.3\cdot 10^{-10} F

Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{0.0163 m}=1.1\cdot 10^{-10} F

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3 years ago
20 Accelerated motion is represented by a<br> line on a nonlinear distance time graph.
Varvara68 [4.7K]

Curved line

Explanation:

Acceleration of motion is represented by a curved line on a non-linear distance-time graph.

The acceleration of a non-linear motion is depicted using a parabola which is a curve. This implies that the velocity is constantly changing and the distance covered by the body is also changing with equal amount of time.

  • A plot of this will give a parabola. This can be further established using one of the equations of motion below:

    x = u + \frac{1}{2}at ²

This is a quadratic function where:

x is the distance

u is the initial velocity

t is the time

a is acceleration

A quadratic function gives a curved line which is a parabola.

Learn more:

Acceleration brainly.com/question/10932946

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deff fn [24]
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Also, work= force X distance. The energy does not go away, but rather get changed into some other form of energy
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