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Agata [3.3K]
3 years ago
11

A man ran a 5 mile race. The race looped around a city park and back

Physics
1 answer:
Tems11 [23]3 years ago
7 0
10 miles common since
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A man is sitting in the outfield bleachers watching a baseball game through binoculars. Which is MOST LIKELY true?
Anestetic [448]
Choice-A is the correct one. It doesn't say it, but it means he'll see the ball reach the catcher's mitt first BEFORE HE HEARS IT slap the mitt.
7 0
4 years ago
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Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of
xxMikexx [17]

Answer:

a. 0.7 m/s

b. The second runner

c. 4.20 meters

Explanation:

a. To know the relative speed we can use the following equation:

Relative Speed (Vr) = V1 - V2

The relative speed is used to compared the velocity of one object (V1) to another object (V2). To learn the Relative Velocity from the second runner to the first we do the following:

Relative Speed (Vr) = Second Runner Velocity (Vs) - First Runner Velocity (Vf)

Vr = 4.20 m/s  - 3.50 m/s

Vr = 0.7 m/s

This means that the second runner is gaining 0.7 meter from the first runner each second.

b. To know which runner will gain the race, we need to keep in mind, that the seconds runner is 45 meter more away that the first runner from the goal. Knowing this, the winner will be the one that reach the goal on less time.

Because movement is constant, we can use the following equation:

Velocity (V) = Distance (D) / Time (T)

To get the time we do:

T = D / V

Now, for the first runner:

T = 250 meters / (3.50 m/s)

T = 71.42 seconds

For the second runner.

T = (250 meters + 45 meters) / (4.20 m/s)

T = 70,23 seconds

Because the second runner takes less time to reach the goal, he wins the race.

c. Because it is know how much time takes the winner to get to the finish line, we can use that same time to know how far was the first runner from the goal. This is posible we know that how far he is from the goal is as follows.

Distance from goal (Dg) = Total Distance (D) - Distance travelled (Dt)

Where Total Distance (D) is 250 mts. And the distance travelled can be obtained by using the following equation.

Velocity (V) = Distance (D) / Time (T)

Searching for distance:

D = V / T.

D = (3.50 m/s) * 70.23 s

D = 245,80 meters

Soo

Distance from goal (Dg) = Total Distance (D) - Distance travelled (Dt)

Dg = 250 meters - 245,80 meters

Dg = 4,20 meters

The first runner was 4,20 meter behind the second one when the second runner crossed the goal

3 0
4 years ago
Read 2 more answers
Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the electric force of
Westkost [7]

Answer:800N

Explanation:

Force of repulsion = kq1q2/r^2

Q1= 20*10^-6

Q2=100*10^-6

R=150cm=0.15m

K= 9*10^9

F= 2*10^-5*1*10^-4*9*10^9/(0.15)^2

F= 2*1*9*10^-5-4+9/(0.15)^2

F= 18*10^0/(0.15)^2

F=18/0.0225

F=800N

7 0
4 years ago
HELPP
Brrunno [24]

Answer:

they are like charges so they magnitude repulsive & direction will be ones left &ones right. but it depends on the axis of rotation.

7 0
2 years ago
At what speed, as a fraction of c, will a moving rod have a length 65% that of an identical rod at rest
dezoksy [38]

Answer:

v/c = 0.76

Explanation:

Formula for Length contraction is given by;

L = L_o(√(1 - (v²/c²))

Where;

L is the length of the object at a moving speed v

L_o is the length of the object at rest

v is the speed of the object

c is speed of light

Now, we are given; L = 65%L_o = 0.65L_o, since L_o is the length at rest.

Thus;

0.65L_o = L_o[√(1 - (v²/c²))]

Dividing both sides by L_o gives;

0.65 = √(1 - (v²/c²))

Squaring both sides, we have;

0.65² = (1 - (v²/c²))

v²/c² = 1 - 0.65²

v²/c² = 0.5775

Taking square root of both sides gives;

v/c = 0.76

6 0
3 years ago
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