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Sauron [17]
2 years ago
13

What is the product of the complex numbers (-3i+4) and (3i+4)?

Mathematics
2 answers:
Nataly_w [17]2 years ago
5 0

Answer: 25

Step-by-step explanation:

Finding the product of complex numbers is not different to finding the product of real numbers

(-3i+4) * (3i+4) = -9i^2 + 12i - 12i + 16 = 25

vladimir1956 [14]2 years ago
4 0

Answer:

25

Step-by-step explanation:

An easy way to multiply binomials is the FOIL(first, outer, inner, last) method. Multiply the first terms of each binomial, -3i×3i=-9i^2. Then do the outer terms, -3i×4=-12i. Then do the inner terms 4×3i=12i. Then do the last terms, 4×4=16. Lastly combine like terms, the -12i and 12 cancel out, and you're left with -9i^2+16. i^2=1, so then you get -9(-1)+16. -9×-1=9. 9+16=25

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If the parent function is \root(3)(x), describe the translation of the function y=\root(3)(x+4)-3
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The parent function moves 4 units right and 3 units down. This is a translation by the vector.

According to the question,

Transformation \sqrt[3]{x} maps  onto \sqrt[3]{x+4} -3 . Take f(x) =  \sqrt[3]{x} and f(x+4)=\sqrt[3]{x+4}.

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f(x+4)=\sqrt[3]{x+4}

f(x+4) - 3=\sqrt[3]{x+4} - 3

Analyze the function to see the translations. f(x-4) corresponds to a horizontal translation 4 units in the positive 'x' direction. f(x)-3 corresponds to a vertical translation 3 units in the negative 'y' direction.

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2 years ago
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3 years ago
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3 years ago
If I have a 62% in a class, what percentage do I need to get on a 50% weighted test grade to have at least a 70% in the class?
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Answer:

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3 years ago
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