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iogann1982 [59]

3 years ago

14

In ptolemy’s earth-centered model for the solar system, venus always stays close to the sun in the sky and, because it always st

ays between earth and the sun, its phases range only between new and crescent. The following statements are all true and were all observed by galileo. Which one provides evidence that venus orbits the sun and not earth?.

1 answer:

sp2606 [1]3 years ago

6 0

Hey, can you state your question a little more clearly

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You performed an experiment in which you measured the amount of water leaking through different types of roofs. For one roof, yo

Ostrovityanka [42]

Given:
m = 13.2 oz, the mass of water measured

Note that
$1 \, oz = (1 \, oz)*( \frac{1}{16} \, \frac{lb}{oz} )*( \frac{1}{2.2} \, \frac{kg}{lb} ) = 0.0284 \, kg$

Answer: 0.0284 kg

6 0

3 years ago

Read 2 more answers

The design of a 60.0 cm industrial turntable requires that it has a kinetic energy of 0.250 j when turning at 45.0 rpm. What mus

Aneli [31]

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

$E_{rot} = \frac{1}{2} I \omega ^2$

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

$\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s$

$E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2$

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

5 0

3 years ago

Calculate the force between two objects that have masses of 70 kilograms and 2,000 kilograms separated by a distance of 1 meter.

Makovka662 [10]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The Gravitational Force between given objects will be ~

$9.34 \times {10}^{ - 6} \: \: N$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

We know that ~

$\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}$

where ~

F = gravitational force

$m_1$ = mass of 1st object = 70 kg

$m_2$ = mass of 2nd object = 2000 kg

G = gravitational constant = $6.674 × {10}^ {-11}$

r = distance between the objects = 1 m

Let's calculate the force ~

$F = \dfrac{6.674 \times 10 {}^{ - 11} \times 70 \times 2000 }{1 {}^{2} }$

$F =6.674 \times 7 \times 2 \times 10 { }^{ - 11} \times 10 {}^{4}$

$93.436 \times 10 {}^{ - 7}$

$9.3436 \times 10 {}^{ - 6} \: \: newtons$

6 0

3 years ago

If R = 12 cm, M = 520 g, and m = 20 g (below), find the speed of the block after it has descended 50 cm starting from rest. Solv

timofeeve [1]

Answer:

v = 0.84 m/s

Explanation:

given,

R = 12 cm

M (mass of pulley )= 520 g

m (mass of block)= 20 g

s = 50 cm = 0.5 m

using conservation of energy

Potential energy = Kinetic energy

$m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2$

$I_{disk}= \dfrac{1}{2}MR^2$ and v = r ω

$m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}(\dfrac{1}{2}MR^2)(\dfrac{v}{R})^2$

$m g h = \dfrac{1}{2}mv^2 +\dfrac{1}{4}Mv^2$

$m g h = \dfrac{1}{2}v^2(m +\dfrac{1}{2}M)$

$v=\sqrt{\dfrac{2mgh}{m + 0.5 M}}$

$v=\sqrt{\dfrac{2\times 0.020 \times 9.8 \times 0.5}{0.02 + 0.5\times 0.52}}$

v = √0.7

v = 0.84 m/s

5 0

3 years ago

What describes how the spring constant affects the potential energy of an object for a given displacement from an equilibrium po

Anit [1.1K]

Answer:

The higher the spring constant, the greater the elastic potential energy.

8 0

3 years ago