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jeyben [28]
3 years ago
13

Any five chapter 9 institutions found in the constitution of south africa

Physics
1 answer:
navik [9.2K]3 years ago
7 0
Five institutions from the chapter 9 found in the constitution of south Africa are : 
- The Public Protector
- The south African Human right commission
- The commission of Gender Equality
- The Auditor- General
- The Independent Electoral Commission

Hope this helps
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- A preliminary stage of a spacecraft was to place it in a parking orbit 190km above the
solniwko [45]
The correct answer is C the time to complete one orbit
8 0
3 years ago
Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
bekas [8.4K]

The correct answer is the following.

The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.

As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.

5 0
3 years ago
We can model the motion of a bumblebee's wing as simple harmonic motion. A bee beats its wings 250 times per second, and the win
zlopas [31]

Answer:

The amplitude of the wing tip's motion is 1.6 mm.

Explanation:

Given that,

Beat = 250 /s

Speed = 2.5 m/s

We need to calculate the amplitude of the wing tip's motion

Using the equation for the maximum velocity

v_{max}=2\pi f A

A=\dfrac{v}{2\pi f}

Where,

v = speed

f = frequency

A = amplitude

Put the value into the formula

A=\dfrac{2.5}{2\pi\times250}

A=0.00159 = 1.59\times10^{-3}\ m

A=1.6\ mm

Hence, The amplitude of the wing tip's motion is 1.6 mm.

3 0
4 years ago
Read 2 more answers
How much does 1 liter of water weigh
Zinaida [17]

Weight = (mass) x (gravity)

On Earth ...

Weight = (1 kg) x (9.8 m/s^2)

Weight = 9.8 Newtons

8 0
3 years ago
At the end of cylindrical rod of length l = 1 m and mass M = 1 kg rotating horizontaly along the vertical axis in its center wit
matrenka [14]

Answer:

w = 0.943 rad / s

Explanation:

For this problem we can use the law of conservation of angular momentum

       

Starting point. With the mouse in the center

            L₀ = I w₀

Where The moment of inertia (I) of a rod that rotates at one end is

         I = 1/3 M L²

Final point. When the mouse is at the end of the rod

          L_{f} = I w + m L² w

As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved

        L₀ = L_{f}

        I w₀ = (I + m L²) w

        w = I / I + m L²) w₀

We substitute the moment of inertia

        w  = 1/3 M L² / (1/3 M + m) L²    w₀

        w = 1 / 3M / (M / 3 + m) w₀

We substitute the values

      w = 1/3 / (1/3 + 0.02) w₀

      w = 0.943 w₀

To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s

        w = 0.943 rad / s

3 0
3 years ago
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