Answer:
Inter quartile range.
Step-by-step explanation:
We have been given that the amount of money that college students spend on rent each month is usually between $300 and $600. However, there are a few students who spend $1,300.
We know that range, interquartile range, variance and standard deviation are the measures of spread.
Since $1300 is large valued outlier as mostly students spend between $300 and $600, so mean of our given data set will be grater than median and our given data is skewed to right.
Since range, variance and standard deviation are not good measure of spread for skewed data, therefore, inter-quartile range would be the most appropriate to measure the amount of money that college students spend on rent per month.
The answer is D sorry about my earlier comment
<span>The answer is 4.16666666666666</span>
Answer:
Sum of the sequence will be 648
Step-by-step explanation:
The given sequence is representing an arithmetic sequence.
Because every successive term of the sequence is having a common difference d = -3 - (-9) = -3 + 9 = 6
3 - (-3) = 3 + 3 = 6
Since last term of the sequence is 81
Therefore, by the explicit formula of an arithmetic sequence we can find the number of terms of this sequence

where a = first term of the sequence
d = common difference
n = number of terms
81 = -9 + 6(n - 1)
81 + 9 = 6(n - 1)
n - 1 = 
n = 15 + 1 = 16
Now we know sum of an arithmetic sequence is represented by

Now we have to find the sum of the given sequence
![S_{16}=\frac{16}{2}[-9 + (16-1)6]](https://tex.z-dn.net/?f=S_%7B16%7D%3D%5Cfrac%7B16%7D%7B2%7D%5B-9%20%2B%20%2816-1%296%5D)
= 8[-9 + 90]
= 8×81
= 648
Therefore, sum of the terms of the given sequence will be 648.
Answer:
25,500
Step-by-step explanation:
550 * 10 = 5500
31,000 - 5500 = 25,500