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2 years ago

8

When using a slinky, you get compressions and rarefactions after a pulse. How do these properties of a longitudinal wave relate

to wavelength and amplitude?

1 answer:

beks73 [17]2 years ago

5 0

Wave

Wavelength

The distance between two compressions or between two rarefactions.

Amplitude

the distance from the equilibrium position to compression or rarefaction

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8. A sample of potassium chlorate (KCIO,) was heated in a test tube and decomposed 2KC?(s) 302 (g) + 2KCIO, (s) The oxygen was c

dangina [55]

Answer:

Partial pressure of $O_{2}$ in the gas was 733 torr and mass of $KClO_{3}$ in the sample was 2.12 g.

Explanation:

a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of $O_{2}$ )

Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.

So, partial pressure of $O_{2}$ = (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr

b) Lets assume that $O_{2}$ behaves ideally. Hence-

PV=nRT

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin

here P = 733 torr = $(733\times 0.001316)atm$ = 0.9646 atm

V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K

So, $n=\frac{PV}{RT}$

= $\frac{(0.9646 atm)\times (0.65 L)}{(0.082 L.atm/(mol.K))\times (295 K)}$

= 0.0259 moles

As 3 moles of $O_{2}$ are produced from 2 moles of $KClO_{3}$ therefore 0.0259 moles of $O_{2}$ are produced from $(\frac{2\times 0.0259}{3})$ moles or 0.0173 moles of $KClO_{3}$ .

Molar mass of $KClO_{3}$ = 122.55 g

So mass of $KClO_{3}$ in sample = $(0.0173\times 122.55)g$

= 2.12 g

7 0

3 years ago

If 6.49 mol of ethane (C2H6) undergo combustion according to the unbalanced equation

MArishka [77]

Answer:

22.715 moles of oxygen are used

Explanation:

Given data:

Number of moles of ethane = 6.49 mol

Number of moles of O₂ required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Now we will compare the moles of oxygen with ethane.

C₂H₆ : O₂

2 : 7

6.49 : 7/2×6.49 = 22.715 mol

Thus, 22.715 moles of oxygen are used.

3 0

3 years ago

Which of these resources are renewable? Check all that apply. natural gas wind minerals forests tides geothermal energy

PolarNik [594]

Here is a list of some renewable resources, I hope these help answer the question, or help to answer it.

-ethanol

-hydropower

-geothermal power

-wind energy

-solar energy

-biomass

(Biomass refers to organic material from plants and animals)

4 0

3 years ago

Which element easily gains one electron to form a negative ion?

sdas [7]

Answer: Fluorine

Explanation: Fluorine has an oxidation state of -1, meaning it gains 1 electron in chemical bonds, forming a negative ion. Magnesium has an oxidation state of +2, nitrogen has -3, and lithium has an oxidation state of +1.

5 0

3 years ago

Read 2 more answers

The recommended daily allowance of niacin (vitamin B3) is 12 mg per day for children. The molecular formula for niacin is C6H5NO

Tom [10]

Answer:

5.87 ×10¹⁹ molecules.

Explanation:

From the question given above, the following data were obtained:

Mass of C₆H₅NO₂ = 12 mg

Number of molecules of C₆H₅NO₂ =?

Next, we shall convert 12 mg to g. This can be obtained as follow:

1 mg = 10¯³ g

Therefore,

12 mg = 12 mg × 10¯³ g / 1 mg

12 mg = 0.012 g

Next, we shall determine the mass of 1 mole of C₆H₅NO₂. This can be obtained as follow:

1 mole of C₆H₅NO₂ = (12×6) + (5×1) + 14 + (16×2)

= 72 + 5 + 14 + 32

= 123 g

Finally, we shall determine the number of molecules present in 12 mg (i.e 0.012 g) of C₆H₅NO₂. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of C₆H₅NO₂ = 6.02×10²³ molecules

123 g of C₆H₅NO₂ = 6.02×10²³ molecules

Therefore,

0.012 g of C₆H₅NO₂ = 0.012 × 6.02×10²³ / 123

0.012 g of C₆H₅NO₂ = 5.87 ×10¹⁹ molecules.

Thus, 12 mg (i.e 0.012 g) of C₆H₅NO₂ contains 5.87 ×10¹⁹ molecules.

4 0

3 years ago