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Lena [83]
3 years ago
7

How many Al atoms are there in 40.5 g of Al foil? Al:27

Chemistry
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

c) 9.03 x 10^23

Explanation:

find the molar mass of Al

Al is 27.0 grams

Then use that, to find the number of moles in Aluminum.

Then use Avogadro's number which is 6.02 * 10^23

After that, write all of that down with dimensional analysis.

40.5 g * 1 mol/ 27.0 g of Al  * 6.02 x 10^23 / 1mol

As your final answer, you will get 9.03 * 10^23 atoms with sig figs.

Hope it helped!

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The formula ca(no3)2 tells us that one formula unit of this compound is composed of ________ calcium atoms, ________ nitrogen at
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Answer:- The formula Ca(NO_3)_2 tells us that one formula unit of this compound is composed of one calcium atom, two nitrogen atoms, and six oxygen atoms.

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When we have subscripts inside and outside the parenthesis then they are multiplied and the outside subscript is considered for all the atoms present inside the parenthesis.

Here, for the given chemical formula, the subscript of N is 1 and the subscript present outside is 2. So, 1 x 2 = 2 and for oxygen, 3 x 2 = 6

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3 years ago
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An emerald gemstone is an impure form of the mineral beryl, Be3Al2Si16O18. What is the percentage of silicon in the mineral?
solong [7]

Answer:

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O: 18 × 16.00 g = 288.0 g

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The mass percentage of silicon is:

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I think the given chart is electronegativity chart.

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Electronegativity increases from left to right of the periodic table and decreases from up to down. 
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