Answer:
3.0242 g of H2
Explanation:
The balanced equation for the reaction is given as;
Cr2O3 + 3H2 → 2Cr + 3H2O
From the reaction, the mole ratio between Cr2O3 and H2 is given as;
1 mol of Cr2O3 reacts with 3 mol of H2
Converting to mass using;
Mass = Molar mass * Number of moles
Cr2O3;
Mass = 151.99 g/mol * 1 mol = 151.99 g
H2;
Mass = 2.016 g/mol * 3 mol = 6.048 g
How many grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, Cr203?
151.99 = 6.048
76 = x
x = 76 * 6.048 / 151.99
x = 3.0242 g
