OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
Answer: 140$
Step-by-step explanation: 15$ times 8 meals plus 20 dollar fee eaquals 140$
Answer:
y - 2 = 3(x + 1)
y - 2 = 3x + 3
y = 3x + 5
Step-by-step explanation:
Y= -3 - 2x because all you have to do is move the 2x over to have an x and a y on different sides, and in order to do that you do the opposite so since it is a positive 2, you subtract it and make it negative
The answer is the first one
