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spin [16.1K]
2 years ago
15

Does 1\2 = 2\3 or would it 1\2 ≤ 2\3

Mathematics
2 answers:
qaws [65]2 years ago
4 0

Answer:

1/2 < 2/3

Step-by-step explanation:

1/2 = .5 in decimal form while 2/3 is .6 repeating in decimal form

DanielleElmas [232]2 years ago
3 0

1/2 < 2/3

*Watch image for better understanding

Blue portion is 1/2

Red portion is 2/3

so, obviously red portion is bigger than blue one.

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What is 45% written as a fraction
Neko [114]
There are 2 ways you can write this.

You can either do /1 or /100

\frac{45}{1} or \frac{45}{100}

The most used is \frac{45}{100}

7 0
3 years ago
Sean lives about 15.5 miles from the airport.which number rounds to 15.5 when rounded to the nearest tenths
stiv31 [10]

Answer: 16

Step-by-step explanation:

7 0
3 years ago
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Lena got three “hits” in her last seven times at bats, so her chance of getting a hit is 3/5. Theoretical or Experimental?
ZanzabumX [31]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
19. 144 miles on 4.5 gallons
stealth61 [152]

Step-by-step explanation:

To find the amount of miles on one gallon,

\frac{144 \div 4.5}{4.5 \div 4.5}  =  \frac{32}{1}

Hence, 32 miles per gallon.

6 0
3 years ago
The time rate of change of a rabbit population PP is proportional to the square root of PP. At time t=0t=0 (months) the populati
frosja888 [35]

Answer:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

Step-by-step explanation:

For this case we cna use the proportional model given by:

\frac{dP}{dt} = k \sqrt{P}

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition P(0) =100 and P'(0) = 10

we can rewrite the differential equation like this:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

6 0
3 years ago
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