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nasty-shy [4]
2 years ago
14

How many unbonded pairs of electrons are found on the alanine molecule

Chemistry
1 answer:
-Dominant- [34]2 years ago
6 0

Answer:

I'm hoping this helps!! it's on quizzes if you're wondering

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In an ionic bond:
Fynjy0 [20]

In an ionic bond :

=》B. one atom accepts electrons from another.

in this bond an atom ( <em><u>metallic</u></em> ) loses its electrons and another atom ( <em><u>non- metallic</u></em> ) accepts the electrons, and since there isn't the equal positive and negative charges in the atoms, they forms <em><u>cations</u></em> ( +ve charge ) and <em><u>anions </u></em>( -ve charge )

and get stacked or <em><u>attracted</u></em> to each other by strong <em><u>electrostatic force</u></em>.

4 0
3 years ago
Read 2 more answers
Mg2OH has how many unique elements?<br> A. <br> 4<br> B. <br> 2<br> C. <br> 3<br> D. <br> 5
frutty [35]

Answer:

Magnesium hydroxide has 3 unique elements.

Explanation:

Long story short, 2 is the balancing compound in structure to make up hydroxide, therefore 1 compound would be left to create Mg(2O)H.

(This is only an opinion of mathematical science to me, I don't have complete understanding of this subject either, good luck.)

5 0
3 years ago
What do u need to know to describe the velocity of an object?
Alex_Xolod [135]
To determine the velocity of an object, you need to know the displacement and the change in time. 

v = displacement / change in time

5 0
3 years ago
Read 2 more answers
What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

3 0
3 years ago
The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of
Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8



5 0
3 years ago
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