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aniked [119]
2 years ago
8

What is a vapor?

Chemistry
1 answer:
BigorU [14]2 years ago
6 0

<em>In physics, a vapor or vapour is a substance in the gas phase at a temperature lower than its critical temperature, implying that the vapor can be condensed into a liquid by increasing the pressure without lowering the temperature. A vapor is not the same as an aerosol.</em>

<em></em>

<em>Please consider marking Brainliest.</em>

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What are the elements in the first period
aliina [53]

Answer:

Explanation:

There are only two elements in the first period: hydrogen and helium. We can explain why there is less elements in the first row in modern theories of atomic structure.

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3 years ago
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A scientist wants to make a solution of tribasic sodium phosphate, na3po4, for a laboratory experiment. How many grams of na3po4
natima [27]

Answer :

The correct answer is for mass of Na₃PO₄ 39.7 g.

Given  : 1) Molarity of Na⁺ ions = 1.00 M or 1.00 \frac{mol}{L}

2) Volume of solution = 725 mL

Converting volume of solution from mL to L :

Conversion factor : 1 L = 1000 mL  

Volume of solution = 725 mL * \frac{1L }{1000 mL}

Volume of solution = 0.725 L


Following steps can be  done to find mass of  :

<u>Step 1 : Write the dissociation reaction of Na₃PO₄ .</u>

Na_3PO_4    3 Na^+  +  PO_4^3^-

<u>Step 2:  Find moles of Na⁺ ions : </u>

Mole of Na⁺ ions can be calculated using molarity formula  which is :Molarity (\frac{mol}{L} ) = \frac{mole of Na^+ }{volume of solution }

Plugging value of Molarity and volume

1.00 \frac{mol}{L} = \frac{Mole of Na^+ ions}{0.725 L}

Multiplying both side by 0.725 L

1.00 \frac{mol}{L}* 0.725 L = \frac{mole of Na^+ ions}{0.725 L} * 0.725 L

<em>Mole of Na⁺ ions = 0.725 mol</em>

<u>Step 3: Find mole ratio of Na₃PO₄ : Na⁺ :</u>

Mole ratio  is found from coefficients from balanced reaction as:

Mole of Na₃PO₄ in balanced reaction = 1

Mole of Na⁺ ion =  3

<em>Hence mole ratio of Na₃PO₄: Na⁺ = 1 : 3 </em>

<u>Step 4 : To find mole of Na₃PO₄ </u>

Mole of Na₃PO₄ can be calculated using mole of Na⁺ ion and Mole ratio as :

Mole of Na_3PO_4= Mole of Na^+  * Mole ratio

Mole of Na_3PO_4 = 0.725 mol  *  \frac{1 mole of Na_3PO_4}{3 mole of Na^+ }

<em>Mole of Na₃PO₄ =  0.242 mol </em>

<u>Step 5 : To find mass of Na₃PO₄</u>

Mole of Na₃PO₄ can be converted to mass of Na₃PO₄ using  molar mass of Na₃PO₄ as :

Mass (g) = mole (mol) * molar mass \frac{g}{mol}

Mass of Na_3PO_4 =  0.242 mol * 163.94 \frac{g}{mol}

Mass of Na₃PO₄ = 39.619 g

<u>Step 6 : To round off mass of Na₃PO₄ to correct sig fig .</u>

The sig fig in 750 mL and 1.00 M is 3 . So mass of Na₃PO₄ can rounded to 3 sig fig as :

Mass of Na₃PO₄ = 39.7 g


8 0
3 years ago
What am I calculating for when solving for 17.0 mL of ethanol, density of ethanol= 0.94 g/mL
True [87]

Answer:

you are caculating for the mass/wight of ethanol

Explanation:

DxV=M

5 0
3 years ago
Which is not a characteristic of minerals
dem82 [27]

I think d is wrong because  Everything else is correct for sure. also, minerals vary in the position they hold and have different chemical compounds.

6 0
2 years ago
Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of
igomit [66]

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.00154 mol/L
  • Initial volume (V₁): 230. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 660. mL

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

5 0
3 years ago
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