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Shtirlitz [24]
3 years ago
7

Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:

Not all entry-fields provided may be needed. Choose "na" in any space where you have no reagent .
a. H2, Pt:
b. H2, Lindlar's Catalyst
c. H2, Ni2B{P-2)
d. Br2, CCI4
e. NaNH2, Mineral oil, heat
f. NH4CI G.
g. t -BuOK, t -BuOH, heat
h. CH3 I
i. CH3CH2 I
Chemistry
1 answer:
Andru [333]3 years ago
3 0

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

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If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it
Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

6 0
3 years ago
Identify each of the following solids as molecular, ionic, or atomic.
Kisachek [45]

Answer :

(A) Br₂ (s) : molecular solids

(B) AgCl (s) : ionic solids

(C) S (s) : atomic solids

(D) CH₄ (s) : molecular solids

Explanation :

Molecular solids : It is defined as the solids in which they are held together by covalent forces, dipole interactions as attractive forces etc.

Ionic solids : It is defined as the solids in which the atoms composed with oppositely charged ions.

Atomic solids : It is defined as the solids in which the molecules are held together by covalent forces and also includes pure substance.

(A) Br₂ (s)

It is molecular solids because they are held together by covalent forces.

(B) AgCl (s)

It is ionic solids because in this atoms composed with oppositely charged ions.

(C) S (s)

It is atomic solids because it is a pure substance.

(D) CH₄ (s)

It is molecular solids because they are held together by covalent forces.

7 0
3 years ago
Lithium β is a solid phase of lithium still unknown to science. The only difference between it and ordinary lithium is that Lith
pychu [463]

Answer:

The density of Lithium β is 0.5798 g/cm³

Explanation:

For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.

we need to calculate the mass of these atoms because density is mass per unit volume.

Atomic mass of Lithium is 6.94 g/mol

Then we calculate the mass of four atoms;

= 4 .atoms*\frac{1.mole}{6.022 X10^{23} .atoms} *\frac{6.94g}{mole} = 4.6097 X10^{-23} g

⇒next, we estimate the volume of the unit cell in cubic centimeter

given the edge length or lattice constant a = 0.43nm

a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm

Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³

⇒Finally, we calculate the density of Lithium β

Density = mass/volume

Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)

Density = 0.5798 g/cm³

3 0
3 years ago
Please Help me if you can!:) i appreciate anything.
enot [183]

Explanation:

1

Number of nucleon =

Molarmassofnucleon

Massofatom

=

1.6726×10

−24

g/nucleon

3.32×10

−23

g

=19.8=20(approximately)

It is given that element comprises of 2 atoms

Hence,number of nucleon = 2×20=40

2

You have 4.70 mol H2O

There are two H atoms in 1 molecule H2O.

Therefore, there must be 2*4.70 = 9.40 mols H in 4.70 mols H2O.

How many mols O in 4.70 mols H2O? That's 4.70 mols, of course.

Said another way, you have 2 mols H for every 1 mol H2O and 1 mol O for every 1 mol H2O.

So for 50 mols H2O you have 100 mols H and 50 mol O.

7 0
2 years ago
A 9.75 L container holds a mixture of two gases at 15 ° C. The partial pressures of gas A and gas B, respectively, are 0.415 atm
sasho [114]

nitro gas and regular hope this helped

3 0
3 years ago
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