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Shtirlitz [24]
3 years ago
7

Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:

Not all entry-fields provided may be needed. Choose "na" in any space where you have no reagent .
a. H2, Pt:
b. H2, Lindlar's Catalyst
c. H2, Ni2B{P-2)
d. Br2, CCI4
e. NaNH2, Mineral oil, heat
f. NH4CI G.
g. t -BuOK, t -BuOH, heat
h. CH3 I
i. CH3CH2 I
Chemistry
1 answer:
Andru [333]3 years ago
3 0

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

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Can someone help please I will give Brainlyiest
kotykmax [81]

Answer:

See Explanation

Explanation:

moles of NH₃ = 11.9g/17.03 g/mol = 0.699 mole

moles of CN₂OH₄ = 1/2(0.699) mole =0.349 mole

Theoretical yield of CN₂OH₄ = (0.349 mole)(60 g/mole) = 20.963 grams

%Yield = Actual Yield/Theoretical Yield x 100%

= 18.5g/20.963g x 100% = 88.25%

7 0
3 years ago
Read 2 more answers
If 11.5 ml of vinegar sample (d=1g/ml) is titrated with 18.5 ml of standardized Sodium hydroxide
insens350 [35]

Answer:

4.83% of acetic acid in the vinegar

Explanation:

3 0
3 years ago
How much heat is absorbed when 447 g of water , Cp = 4.184 J/goC, goes from 25.0 oC to 35.0 oC?
Digiron [165]

Answer:

The answer to your question is  Q = 18702.5 J

Explanation:

Data

mass of water = m = 447 g

Cp = 4.184 J/g°C

Temperature 1 = T1 = 25°C

Temperature 2 = T2 = 35°C

Heat = Q = ? Joules

Process

1.- Write the formula to calculate heat

    Q = mCp(T2 - T1)

2.- Substitution

    Q = (447)(4.184)(35 - 25)

3.- Simplification

    Q = (447)(4.184)(10)

4.- Result

    Q = 18702.5 J

8 0
3 years ago
What is the volume of an object with the mass of 7.9 grams in the density of 2.28g/ml.
Schach [20]

Answer:

3.7mL is the volume of the object

Explanation:

To convert the mass of any object to volume we must use density that is defined as the ratio between mass of the object and the space that is occupying. For an object that weighs 7.9g and the density is 2.28g/mL, the volume is:

7.9g * (1mL / 2.28mL) =

<h3>3.7mL is the volume of the object</h3>
7 0
2 years ago
Quincy wants to see a real example of rock weathering. Where would be the best place for him to go? A. up on the roof of his hou
zhannawk [14.2K]

Answer:

Option (D)

Explanation:

Weathering is usually defined as the disintegration of rocks at the surface of the earth. This break down of rocks is mainly caused by the geological processes that occur on the earth's surface. This process results in the formation of sediments that are transported and deposited in a new environment.

This weathering process primarily takes place in three different ways such as-

  • Physical weathering- Here, the rocks are broken down by the physical agents such as wind, water, ice.
  • Chemical weathering- Here the rocks are broken down when interacts with the chemical containing water.
  • Biological weathering- here, the rocks are broken down due to the activities done by organisms such as plants and animals.

In the given condition, Quincy can see a real example of rock weathering in the high mountainous region, as in the mountainous region the rocks are frequently weathered and eroded by the agents such as wind, water, and ice.

Thus, the correct answer is option (D).

4 0
3 years ago
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