Answer:
x²+6x+9=0
x²+3x+3x+9=0
x(x+3)+3(x+3)=0
(x+3)(x+3)=0
either
x+3=0
x=-3
or
x+3=0
x=-3
Step-by-step explanation:
next method
x²+6x+9=0
x²+2×x×3+3²=0
it is in formula of (x+y)²
(x+3)²=0
x+3=√0
x+3=0
x=-3
The color that has the greatest difference between the theoretical and experimental probability is yellow.
<h3>Which color has the greatest difference?
</h3>
Theoretical probability of each color = number of color in each section / total number of sections
1/5 = 0.2
Experimental probability is based on the result of an experiment that has been carried out multiples times
Experimental probability
Experimental probability of choosing orange = 118 / 625 = 0.19
Difference = 0.2 - 0.19 = 0.01
Experimental probability of choosing purple = 137 / 625 = 0.22
Difference 0.22 - 0.2 = 0.02
Experimental probability of choosing brown = 122 / 625 = 0.20
0.2 - 0.2 = 0
Experimental probability of choosing yellow = 106 / 625 = 0.17
0.20 - 0.1696 = 0.0304
Experimental probability of choosing green = 142 / 625 = 0.23
0.2272 - 0.20 = 0.0272
To learn more about experimental probability, please check: brainly.com/question/23722574
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Answer:
Area of remaining cardboard is 224y^2 cm^2
a + b = 226
Step-by-step explanation:
The complete and correct question is;
A rectangular piece of cardboard is 16y cm long and 23y cm wide. Four square pieces of cardboard whose sides are 6y cm each are cut away from the corners. Find the area of the remaining cardboard. Express your answer in terms of y. If your answer is ay^b, then what is a+b?
Solution;
Mathematically, at any point in time
Area of the cardboard is length * width
Here, area of the total cardboard is 16y * 23y = 368y^2 cm^2
Area of the cuts;
= 4 * (6y)^2 = 4 * 36y^2 = 144y^2
The area of the remaining cardboard will be :
368y^2-144y^2
= 224y^2
Compare this with;
ay^b
a = 224, and b = 2
a + b = 224 + 2 = 226
<span><span><span>1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. </span>
(Scroll Down for Answer!)</span><span>Answer by </span>jim_thompson5910(34047) (Show Source):You can put this solution on YOUR website!
<span>If we plot the points and connect them, we get this triangle:
Let point
A=(xA,yA)
B=(xB,yB)
C=(xC,yC)
-------------------------------
Let's find the equation of the segment AB
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through AB is
-------------------------------
Let's find the equation of the segment BC
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through BC is
-------------------------------
Let's find the equation of the segment CA
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through CA is
So we have these equations of the lines that make up the triangle
So to find the equation of the line that is perpendicular to that goes through the point C(2,-5), simply negate and invert the slope to get
Now plug the slope and the point (2,-5) into
Solve for y and simplify
So the altitude for vertex C is
Now to find the equation of the line that is perpendicular to that goes through the point A(4,5), simply negate and invert the slope to get
Now plug the slope and the point (2,-5) into
Solve for y and simplify
So the altitude for vertex A is
Now to find the equation of the line that is perpendicular to that goes through the point B(-4,1), simply negate and invert the slope to get
Now plug the slope and the point (-4,1) into
Solve for y and simplify
So the altitude for vertex B is
------------------------------------------------------------
Now let's solve the system
Plug in into the first equation
Add 2x to both sides and subtract 2 from both sides
Divide both sides by 3 to isolate x
Now plug this into
So the orthocenter is (-2/3,1/3)
So if we plug in into the third equation , we get
So the orthocenter lies on the third altitude
</span><span>
</span></span>
length = 8ft
height = 4 in
width = w ft --> u looking for this
convert in to ft for the height:
4 in (1 ft / 12 in) = 1/3 ft
You know that:
1 cubic yard = $ 98
? cubic yard = $58.07
Solve for ? cubic yard:
? cubic yard = 58.07/98 = 0.592551
convert this in cubic feet:
1 yard = 3 feet
0.59255 cubic yard (27 cubic ft/1 cubic yard) = 15.99887755 cubic ft
Now solve for the width:
length x width x height = ? cubic ft.
width = ? cubic ft / (length x height) =15.99887755 cubic ft/[(8ft)(1/3 ft )] = 5.999579082 ft
approx 6 ft
