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2 years ago

When atoms gain electrons, they can become larger, because the addition of an electron increases electrostatic repulsion.

Chemistry

1 answer:

astra-53 [7]2 years ago

6 0

Answer:True

Explanation: An anion has a larger radius than a neutral atom because it gains valence electrons. There are added electron/electron repulsions in the valence shell that expand the size of the electron cloud, which results in a larger radius for the anion.

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Give the formula of a compound in unpolluted air

77julia77 [94]

Carbon dioxide and oxigen

6 0

3 years ago

The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.

torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

$Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}$

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0

2 years ago

Sodium hydroxide (NaOH) and elemental sodium (Na)

Olegator [25]

Answer:

If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.

Explanation:

6 0

2 years ago

Yucca moths lay eggs in yucca flowers. When the eggs hatch, the larvae eat yucca seeds. The moths help pollinate the flowers. Wh

liberstina [14]

A. Mutualism. This is because both the larvae and the flower are benefited. The larvae is fed, and the flower is pollinated.

Hope this helps!

8 0

3 years ago

7.02 x 10^23 molecules of X2, a ssubstance consisting of diatomic molecules, has a mass of 296 grams. Determine the atomic weigh

Fiesta28 [93]

Answer:

d. 127 g/mol.

Explanation:

Hello!

In this case, since we have the amount of molecules of this this compound, we are able to compute the moles out there by using the Avogadro's number:

$mol=7.02x10^{23}molec*\frac{1mol}{6.022x10^{23}molec}=1.17mol$

Which correspond to the moles of X2. Then, by using the mass we are able to compute the molar mass of X2:

$MM=\frac{296g}{1.17mol}\\\\MM=254g/mol$

It means that the atomic mass of X halves the molar mass of X2, which is then d. 127 g/mol.

Best regards!

4 0

2 years ago