Answer:
0.1410 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
The mole ratio of the acid, HCl (nA) = 1
The mole ratio of the base, NaOH (nB) = 1
Next, the data obtained from the question. This include:
Volume of acid, HCl (Va) = 25 mL
Volume of base, NaOH (Vb) = 34.55 mL
Concentration of base, NaOH (Cb) = 0.1020 M
Concentration of acid, HCl (Ca) =?
CaVa / CbVb = nA/nB
Ca × 25 / 0.1020 × 34.55 = 1/1
Ca × 25 / 3.5241 = 1/1
Cross multiply
Ca × 25 = 3.5241 × 1
Ca × 25 = 3.5241
Divide both side by 25
Ca = 3.5241 / 25
Ca = 0.1410 M
Therefore, the concentration of the acid, HCl is 0.1410 M
