First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
Answer:
1.90 L
Explanation:
Using Boyle's law
Given ,
V₁ = 595 L
V₂ = ?
P₁ = 1.00 atm
P₂ = 55.0 atm
Using above equation as:
<u>The volume would be 1.90 L.</u>
Answer:
0.0014 moles is present in 40cm³ of 0.035M of HCl solution
Explanation:
Molarity = 0.035M
V = 40.0mL
1mL = 1cm³
V = 40cm³
0.035 moles = 1000cm³
X moles is present in 40cm³
X = (40 * 0.035) / 1000
X = 0.0014moles
0.0014 moles is present in 40cm³ of solution
The ionic eqn is as follow:
1 Al(OH)3(s) + 3 H+(aq) + 3 NO3(-1) --> 1 Al(3+)(aq) + 3 NO3(-)(aq) + 3 H2O(l)
3moles of No3- ion on both sides cancels out to give the net ionic eqn:
1 Al(OH)3(s) + 3 H+(aq) --> 1 Al(3+)(aq) + 3 H2O(l)
