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Inessa [10]
3 years ago
14

The reaction 2KClO3(s) --> 2KCl(s) + 3O2(g) is a(n)

Chemistry
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

decomposition reaction.

Explanation:

It is a decomposition reaction as potassium chlorate compound breaks to form potassium chloride and oxygen. This reaction requires heat as source of energy to break down the compound so it is endothermic in nature.

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What mass of chloride gas will react with 96.6g of sodium?
Oduvanchick [21]
Molar mass :

Cl₂ =  71.0 g/mol        Na = 23.0 g/mol

<span>2 Na + Cl</span>₂<span> = 2 NaCl
</span>
2 x 23 g Na -------> 71.0 g Cl₂
96.6 g Na ----------> ?

Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )

Mass Cl₂ = 6858.6 / 46

= 149.1 g of Cl₂

hope this helps!

8 0
3 years ago
Calculate the percent composition of Ca3P2
Afina-wow [57]
Calculate the molar mass of Ca3P2 in grams per mole or search for a chemical formula or substance.
8 0
3 years ago
Read 2 more answers
What is the mass in grams of BaCl2 that is needed to prepare 200 mL of a 0.500 M solution
DENIUS [597]

Answer:

= 20.82 g of BaCl2

Explanation:

Given,

Volume = 200 mL

Molarity = 0.500 M

Therefore;

Moles = molarity × volume

          = 0.2 L × 0.5 M

          = 0.1 mole

But; molar mass of BaCl2 is 208.236 g/mole

Therefore; 0.1 mole of BaCl2 will be equivalent to;

  = 208.236 g/mol x 0.1 mol

  = 20.82 g

Therefore, the mass of BaCl2 in grams required is 20.82 g

6 0
3 years ago
Milkweed contains a poison known as cardenolides. Monarch butterflies eat the milkweed plant and hold on to this toxic compound.
igor_vitrenko [27]

Answer:

the answer is D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms

Explanation:

i took the test and got a 100%

4 0
2 years ago
If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?
Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

\tt \dfrac{5000~g}{46~g/mol}=108.7~moles

moles of glucose to produce 108.7 moles ethanol :

\tt \dfrac{1}{2}\times 108.7=54.35

54.35 moles = 5 hours

moles of 1000 kg of glucose :

\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles

So for 5555.5 moles, it takes :

\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days

7 0
3 years ago
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