The molality of a 0.677 m ethanol ( c 2 h 5 o h ) solution whose density is 0.588 g/ml.
What is molality and molarity?
The number of solvent moles per kilogram is known as molality. Because the mass of the solute and solvent in the solution remains constant, molality is the preferred concentration transfer method.
Molarity, also referred to as molar concentration, is the quantity of a material expressed as moles per litre of solution. Solutions marked with a molar concentration have a capital M. One mole of solvent per litre is present in a 1.0 M solution.
Molar mass (w) of C2H5OH = 46g
Molarity(M) = 0.677M
Density(D) = 0.588g/mol
<u>Molality(m)</u><u> = M/D * (1000 + w*M)</u>
<u>= 1187.2m</u>
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It’s a nonet because an octet is 8, a quartet is 4, and a duet is 2.
Answer:
The value of Kc is 9.33 * 10^-17
Explanation:
Step 1: Data given
Temperature = 1000 K
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Step 2: Calculate Kc for N₂ (g) + 2 O₂ ⇌ N₂O₄
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
2 NO₂ (g) ⇌ N₂O₄ (g) = 1/Kc = 1 / 1.5 * 10^6 = 6.67 *10^-7
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Kc = Kc1 * Kc2
Kc = (6.67 *10^-7) * (1.4 * 10^-10)
Kc = 9.33 * 10 ^-17
The value of Kc is 9.33 * 10^-17
Zn because it has more strength into it
