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IrinaVladis [17]
2 years ago
15

A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 42 g of water (with an

initial temperature of 20 °C) in a calorimeter. The final temperature of the system is 52.1°C. The specific heat of water is 4.184 J/g*⁰C. What is the specific heat of the metal?
Chemistry
1 answer:
kogti [31]2 years ago
8 0

The piece of unknown metal is in thermal equilibrium with water such that Q of metal is equal to Q of the water. We write this equality as follows:

-Qm = Qw

Mass of metal (Cm)(ΔT) = Mass of water (Cw) (ΔT)

where C is the specific heat capacities of the materials.

We calculate as follows:

-(Mass of metal (Cm)(ΔT)) = Mass of water (Cw) (ΔT)

-68.6 (Cm)(52.1 - 100) = 42 (4.184) (52.1 - 20)

Cm = 1.717 -----> OPTION C

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Answer:

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For the problem:

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Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

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As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

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<em></em>

I hope it helps!

7 0
3 years ago
Is this right????????????
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Answer: yea its right

Explanation:

5 0
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