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shepuryov [24]
2 years ago
8

Help me by today please, brainliest will be given :)

Mathematics
2 answers:
bagirrra123 [75]2 years ago
4 0

Answer:

It's 20 Mystery DVDs

Step-by-step explanation:

If you'll count on the Drama DVDs, it's 32 and 8 boxes meaning each box represents 4. Multiply it to the MDVDs, so 20.

Pachacha [2.7K]2 years ago
3 0

Answer:

20 DVDs

Step-by-step explanation:

5/8 of 32 Drama DVDs = Mystery DVDs

= 32 x 5/8

= 4 x 5

= 20 DVDs

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The graph of a quadratic function with vertex (3, 1) is shown in the figure below. Find the domain and the range. Write your ans
Snezhnost [94]

Answer:

<u>There is no restriction to domain:</u>

  • x = (-∞, +∞)

<u>The range is to vertex coordinate of 1:</u>

  • y = [1, +∞)
4 0
3 years ago
Find the equation of the line with a slope of 3/4 and passes through (4-2)
Ira Lisetskai [31]

Answer:

y = 3/4x - 5

Step-by-step explanation:

An equation of a line can be written in slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept.

Let's plug in what we know.

The slope is 3/4.

y = 3/4x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = 3/4(4) + b

To find b, multiply the slope and the input of x(4)

-2 = 3 + b

Now, subtract 3 from both sides to isolate b.

-5 = b

Plug this into your standard equation.

y = 3/4x - 5

This is your equation. It has a slope of 3/4, and passes through (4, -2)

Hope this helps!

5 0
2 years ago
Please I really need help with 10-17
Ira Lisetskai [31]
This is for number 10

6 0
3 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
PLZ ANYONE help me PLZHELP ME ITS DUE RIGHT NOW
Effectus [21]
AH and GB are congruent
4 0
2 years ago
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