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3 years ago

I NEED HELP RIGHT NOW PLEASE HELP

Mathematics

1 answer:

MatroZZZ [7]3 years ago

6 0

Q1)
11 * 260 / 4 = 715

answer
715 p

Q2)
15 * 130 / 10 = 195

answer
195 €

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Which ordered pairs in the form (x, y)(x, y) are solutions to the equation

Doss [256]

(−6, −14)(−1, −7)
are the answers

hey! are you in 8th grade K12? if so you should join my study group on skype! if you are interested just say the word and ill send you a invite! and if you cant get skype then we can use "discord", which you can use on a web browser!
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7 0

3 years ago

Share £90 in the ratio 1:5 HELP ME PLEASE

ZanzabumX [31]

Answer:

the answer is 15:75

Step-by-step explanation:

(1+5)=6

£90/6=15

So, (1×15):(5×15)

=15:75

7 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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2 years ago

A system of linear inequalities is shown below:

Yuki888 [10]

The 4th selection is appropriate:
The first line is a dashed line which joins ordered pairs (-2, 1) and (3, 1). The second line is a dashed line and joins ordered pairs (-2, -2) and (3, 3). The portion common above the first line and above the second line is shaded