The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
what
Step-by-step explanation:
<span>Answers:
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</span><span>[B]: The 8 in the tenths place is 10 times the value of the 8 in the hundredths place.
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<span>[C]: The 8 in the hundredths place is 10 times the value of the 8 in the tenths place.
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To calculate expected value,
We can add up the probability of all possible events.
The 2 possible events are either winning $50 or losing the prize, which is $ - 50
Expected value =
50 x 40 % + (-50) x 60%
= $-10
So the answer is $-10
First, let's find out how many 5/6 pound bags he can fill with on 2 pound bag.
2 divided by 5/6
2 x 6/5
2.4
He can fill 2.4 bags with one 2 bag.
Now we just need to multiply 2.4 by a number that will make it a whole number. You can use the guess and check method starting with 2 to figure your answer out, but 2.4 x 5 = 12 which is a whole number.
This means that Chad needs to buy 5 of the 2 pound bags to fill 12 of the 5/6 pound bags, and he will not have peanuts leftover
