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Yakvenalex [24]
2 years ago
9

Determine the percent composition by mass of oxygen in the compound C6H1206

Chemistry
1 answer:
inysia [295]2 years ago
3 0

Answer

% of oxygen(O) in glucose = 96/ 180 × 100 = 53.33

Explanation:

so the mass of oxygen in 1 mole of glucose = 6 × 16.00 g = 96.00 g. % oxygen = 96.00 × 100 % = 53.3 % by mass.

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