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wel
3 years ago
5

The nuclear fission process releases neutrons and

Chemistry
1 answer:
yuradex [85]3 years ago
3 0
<span>the answer is c. energy</span>
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Mitotic cyclins control the progression of S phase and mitosis. G1 phase and G2 phase. S phase and G2 phase. G2 phase and mitosi
kotegsom [21]

Answer:

The cell cycle involves different stages such as interphase, the Mitotic phase followed by cytokinesis.

The interphase involves G0 phase, G1 phase, Synthesis or S phase and G2 phase. The G stands for Gap phase.

The interpase involves the preparation of cellular contents, duplication of DNA. Then during mitosis karyokinesis occurs which is the division of duplicated chromosomes. And then through cytokinesis, the cytoplasmic contents also divides yielding two daughter cells.

Most of the cells normally enter into resting phase I.e., G0 phase and then start the process of cell division again. But some cells enter into G0 phase after the division and remain for longer duration. And this stage is called as quiescent or inactive stage. The mature heart muscle cell and nerve cell are the typical examples for this.

There are also some checkpoints in the cell cycle to check for any damage in the DNA from one phase to another phase and is mediated by Cyclins.

Apart from cyclins, the cyclin-dependent kinase also control the cell division.

These kinases are the enzymatic proteins which were activated by the binding of cyclins to it.

As the levels of different cyclins were different at each phase the amount of kinase activity is also regulated.

The kinases phosphorylates the target proteins which inturn helps in cell cycle such as break down of nuclear membrane during mitotic phase and promoting DNA replication in interphase.

These kinases were also down regulated by phosphorylating the sites where cyclin binds.

Therefore, cyclin dependent kinases can control cell cycle activities.

So, the correct answer is 'Cell cycle activities'

7 0
3 years ago
Read 2 more answers
A 35.0 mL sample of 1.00 M KBr and a 60.0 mL sample of 0.600 M KBr are mixed. The solution is then heated to evaporate water unt
Katarina [22]

Answer: The molarity of KBr in the final solution is 1.42M

Explanation:

We can calculate the molarity of the KBr in the final solution by dividing the total number of moles of KBr in the solution by the final volume of the solution.

We will first calculate the number of moles of KBr in the individual sample before mixing together

In the first sample:

Volume (V) = 35.0 mL

Concentration (C) = 1.00M

Number of moles (n) = C × V

n = (35.0mL × 1.00M)

n= 35.0mmol

For the second sample

V = 60.0 mL

C = 0.600 M

n = (60.0 mL × 0.600 M)

n = 36.0mmol

Therefore, we have (35.0 + 36.0)mmol in the final solution

Number of moles of KBr in final solution (n) = 71.0mmol

Now, to get the molarity of the final solution , we will divide the total number of moles of KBr in the solution by the final volume of the solution after evaporation.

Therefore,

Final volume of solution (V) = 50mL

Number of moles of KBr in final solution (n) = 71.0mmol

From

C = n / V

C= 71.0mmol/50mL

C = 1.42M

Therefore, the molarity of KBr in the final solution is 1.42M

5 0
3 years ago
A chemistry student needs of isopropenylbenzene for an experiment. He has available of a w/w solution of isopropenylbenzene in a
Lera25 [3.4K]

Question:

A chemistry student needs of 10 g isopropenylbenzene for an experiment. He has available 120 g of a 42.7% w/w solution of isopropenylbenzene in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Answer:

The answer to the question is as follows

The mass of solution the student should use is 23.42 g.

Explanation:

To solve the question we note the following

A solution containing 42.7 % w/w of isopropenylbenzene in acetone  has 42.7 g of isopropenylbenzene in 100 grams of the solution

Therefore we have 10 g of isopropenylbenzene contained in

100 g * 10 g/ 42.7 g = 23.42 g of solution

Available solution = 120 g

Therefore the quantity to used from the available solution = 23.42 g of the isopropenylbenzene in acetone solution.

8 0
3 years ago
Which of the following is an example of an exothermic reaction? silt settling out of muddy water, bubbles forming in soda, photo
Rudik [331]
Fireworks
An exothermic reaction is one where the products have lower energy than the reactants, so the reaction yields energy. The chemical compounds present in firework fuel release a lot of energy upon oxidation. Photosynthesis is endothermic, settling of silt is not a chemical reaction, it is a physical change. Finally, the bubble formation in soda is not exothermic; otherwise, the sodas would become very hot very fast.
4 0
3 years ago
What is the scientific method?
ohaa [14]
C. a scientific approach to answering questions
6 0
3 years ago
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