Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
Answer:
2,436
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
because it doesn't have an x number written twice like for example
(2,0) (2,8) (3,0)
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
f(x) = x^2 - 2x + 6
to find f(-1), we sub in -1 for every x
f(-1) = (-1^2) - 2(-1) + 6
f(-1) = 1 + 2 + 6
f(-1) = 9 <=======
