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Tems11 [23]
3 years ago
6

I am confused and dont know what to do .....

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer:

Try negative 10

Step-by-step explanation:

I took the test

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Hey, I was wondering, what is 3(6m)+m??? Who can help me???
N76 [4]
<span>What is 3(6m) + m?

3(6m) + m = 
m becomes 1m
9m + 1m =
10m

3(6m) + m is 10m when combining like terms. </span>
6 0
3 years ago
Use the working backward method to find the solution of the equation.
Dahasolnce [82]

Answer:

y=2

Step-by-step explanation:

7y-1=13

+1 +1

7y=14

/7 /7

y=2

3 0
3 years ago
Read 2 more answers
The height (h) of a fireball launched from a Roman candle with an initial velocity of 64 feet per second is given by the equatio
Zigmanuir [339]

Answer: C or 2 seconds.

Step-by-step explanation:

To find the vertex in a standard form equation: (-b/2a,f(-b/2a))

plug it in: -64/2*-32 = 2

3 0
4 years ago
The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0
Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: E(aX)=aE(X), the mean of W will be:

\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55

Applying the property of the variance: V(aX+b)=a^2V(X), the variance of W will be:

\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75

The mean standard deviation of W will be the squared root of V(W):

\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0
4 years ago
According to the graph, what is the experimental probability of selecting the letter E?
Daniel [21]

The experimental probability of letter E is: 3/25

Step-by-step explanation:

The given diagram is the number of outcomes for each letter is given

We have to find the total number of outcomes for finding the experimental probability of letter E

So,

Total outcomes = n(S) = 5+12+8+10+6+9 = 50

Number of outcomes for Letter E = n(E) = 6

So the experimental probability will be:

P(E) = \frac{n(E)}{n(S)}\\\\=\frac{6}{50}\\\\= \frac{3}{25}

Hence,

The experimental probability of letter E is: 3/25

Keywords: Probability, experimental probability

Learn more about probability at:

  • brainly.com/question/10610299
  • brainly.com/question/10688256

#LearnwithBrainly

7 0
3 years ago
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