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brilliants [131]
2 years ago
8

Find the empirical formula of the compound which contains 67.6% Hg, 10.8% S, and 21.6% O.

Chemistry
1 answer:
WINSTONCH [101]2 years ago
7 0

Explanation:

Divide 67.6% by 201 of mercury

Divide 10.8% by 32 of sulfur

Divide 21.6% by 16 of oxygen

Then divide number by itself .

Example : Divide 2.97 by both sulfer moles and oxygen moles . Multiply by 2 to get whole number

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Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2
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Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

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Coefficients:

Reagents  :  Na = 2
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