Arrange ZN HG CU AU metals in order of decreasing activity with the most active first

STALIN [3.7K]

Pitch is sometimes defined as the fundamental frequency of a sound wave. For most practical purposes, this is fine, and pitch and frequency can be thought of as equivalent. On the other hand, for most practical purposes, amplitude can be thought of as volume.

However, technically, pitch and volume are human perceptions. Thus, our perception of pitch and volume are not solely based on frequency and amplitude respectively, but are based on a combination of both. Frequency overwhelming dictates perceived pitch, but amplitude also does have some small, small effect on our pitch perception, especially when it is very large. For example, a very loud sound can have a different perceived pitch than you would predict from its frequency alone.

Hope that helps!

6 0

3 years ago

A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul

ioda

Answer:

%age Yield = 85.36 %

Solution:

The Balance Chemical Reaction is as follow,

C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O

According to Equation ,

100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀

So,

4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀

Solving for X,

X = (4.0 g × 82 g) ÷ 100 g

X = 3.28 g of C₆H₁₀ (Theoretical Yield)

As we know,

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

%age Yield = (2.8 g ÷ 3.28 g) × 100

%age Yield = 85.36 %

5 0

3 years ago

A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfa

love history [14]

<u>Answer: </u>The volume of the solution is 85.7 mL

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}$ .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of $BaSO_4$ = 12.00 g

We know, molar mass of $BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol$

Putting values in equation 1, we get:

$0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL$

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

5 0

3 years ago

How many sulfur atoms are present in 25.6 g of Al2(S2O3)3

IgorC [24]

Given the mass of $Al_{2}(S_{2}O_{3})_{3}$ =25.6 g