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alexgriva [62]
3 years ago
11

Solve for h and c to find what h and c equals; 34.50=4h+7c and 30.50=8h+3c

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0
34.5=4h+7c
(34.5-7c)/4=h
Put h= (34.5-7c)/4 into another equation
30.5=8h+3c
30.5=2(34.5-7c)+3c
30.5=69-14c+3c
11c=38.5
c=38.5/11
Put c=38.5/11 into one of the equations
to calculate the h.


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Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

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3 years ago
Evacuate the following using suitable identities (102)^3
snow_lady [41]

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

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Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

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I hope it helps

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