Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
The value of
exists 1061208.
<h3>How to estimate the value of

?</h3>
Let us rewrite
as 
Now utilizing the identity
, we get
a = 100 and b = 2 then substitute the values of a and b then
![(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]](https://tex.z-dn.net/?f=%28100%2B2%29%5E3%3D100%5E3%2B2%5E3%2B%5B%283%5Ctimes100%5Ctimes2%29%28100%2B2%29%5D)
= 1000000 + 8 + (600 × 102)
= 1000000 + 8 + 61200
= 1061208
Hence, 
Therefore, the value of
exists 1061208.
To learn more about cubic polynomial equation refer to:
brainly.com/question/28181089
#SPJ9
Answer:
By putting some values of x find the y values
Step-by-step explanation:
for example, let x=-1 and x=2y
then -1=2y
y=-1/2
I hope it helps
33 - 4 = 29.
29 / 2 = 14.5
She traveled 14.5 miles in the cab.
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