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shtirl [24]
4 years ago
7

This is what scientists call Newton's cradle. It is a handy devise used to illustrate many concepts in physics.

Physics
2 answers:
Vikentia [17]4 years ago
7 0

According to Newton's third law of motion, "The single ball on the left will move as high as the ball on the right  was dropped" is the expected  result once the ball hits the ball closest to it.

Answer: Option A

<u>Explanation:</u>

Newton’s cradle is the best example for law of conservation of momentum. So that means that energy or momentum exhibited by a particle can be transferred to its nearer object with equal force. So in the given options the first option is correct. As when the right ball is dropped it will collide with its neighboring ball and transfer energy.

By this transferring of energy from one particle to another, it will reach the leftmost ball. But there will be no loss in the energy as the left ball will move as high position as the ball on the right was dropped from. So that means the energy is conserved in the cradle.

Dmitriy789 [7]4 years ago
7 0

A)

The single ball on the left will move as high as the ball on the right was dropped. When you lift the ball on the right, it comes back down with a force and the energy is transmitted through the three balls in the center to the ball on the far left. The ball on the far left then moves with a motion that is equal and opposite to the motion of the ball that you lifted.

HOPED THIS HELPED!!!!!!

(T_T)

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Answer:

U = - G m M / r

Explanation:

The gravitational potential energy is given by the expression

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Do you think copper would have oxidized of it was completly submerged in vinigar
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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d
Georgia [21]

Answer:

Spontaneous processes are characterized by the overall conversion of order to disorder.

Explanation:

The second law of thermodynamics states that: A spontaneous process occurs only if there is an increase in entropy of a system and its surroundings.

Entropy, S, is a measure of the randomness or disorder of a system. It is measured in J/Kmol.

The change in entropy, ∆S = ∆H/T

Where ∆H = change in enthalpy, T = Temperature in Kelvin.

For,

I. An endothermic reaction, ∆S = positive (that is, ∆S is greater than zero), there is an increase in entropy, therefore, the reaction is spontaneous.

II. An exothermic reaction, ∆S = negative (that is, ∆S is less than zero) there is a decrease in entropy, so, the reaction is non-spontaneous.

III. A system at equilibrium, ∆S = 0.

Then,

The standard change in entropy of a reaction, ∆So reaction , is the difference in the standard entropies between products and reactants:

∆So reaction = n ∆Soproducts - m ∆Soreactants

Where, = sigma = sum of,

∆ = delta = change in,

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3 years ago
A person standing 1.20 m from a portable speaker hears its sound at an intensity of 5.50 ✕ 10−3 W/m2. HINT (a) Find the correspo
iris [78.8K]

Answer:

PART A)

L = 97.4 dB

PART B)

I = 6.11 \times 10^{-6} W/m^2

PART C)

L = 67.9 dB

Explanation:

PART A)

level of sound is given as

L = 10 Log\frac{I}{I_o}

now we have

L = 10 Log\frac{5.50\times 10^{-3}}{10^{-12}}

L = 97.4 dB

PART B)

Since source is a spherical source

so here the intensity of sound is inversely depends on the square of the distance from the source

\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}

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I_2 = 6.11 \times 10^{-6} W/m^2

PART C)

level of sound is given as

L = 10 Log\frac{I}{I_o}

now we have

L = 10 Log\frac{6.11\times 10^{-6}}{10^{-12}}

L = 67.9 dB

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3 years ago
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