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2 years ago

Please help, I will give Brainliest!!! :D

Mathematics

1 answer:

anygoal [31]2 years ago

4 0

Step-by-step explanation:

Firstly, notice that this shape is composed of ³/₄ of a circle and ¹/₂ of a square;

The lower left part is the ¹/₂ square, with only 2 sides (a left and lower side) of length 3 units;

The perimeter of this part of the shape is simply the sum of the two sides:

3 + 3 = 6

The remaining part is the ³/₄ circle, which has a radius of 3 units;

The circumference of a circle is found by the formula:

πd

d = diameter = 2 × radius

We only have ³/₄ of the circle, however, so we only have ³/₄ the circumference:

³/₄ × π(2(3)) = ³/₄ × 6π

= ⁹/₂π (or, equally, 4.5π)

So the total perimeter is the sum of the perimeter of the ¹/₂ square and the ³/₄ circle:

4.5π + 6

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Simplify the expression 3(b+5)+b+2

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3(b+5)+b+2=

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The scores of individual students on the American College Testing (ACT) Program College Entrance Exam have a normal distribution

tekilochka [14]

Answer:

The probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

Step-by-step explanation:

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$\{Yi=0, Xi< 19\\Yi=1, Xi\geq 19\}$

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Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{n}X_i\~{}N(n\mu, \sqrt{n}\sigma),\displaystyle\sum_{i=1}^{400}X_i\~{}N(7440, 372)$

Then:

$P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)=1-P(0$

$P(\displaystyle\sum_{i=1}^{n}Y_i=1)=P(\displaystyle\sum_{i=1}^{400}Y_i=1)$

Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{400}Y_i\~{}N(400\times 0.473, \sqrt{400}\times 0.499)=\displaystyle\sum_{i=1}^{400}Y_i\~{}N(189.2; 9.98)$

$P(\displaystyle\sum_{i=1}^{400}Y_i=1)\~{=}P(0.5$

Then:

the probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

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3 years ago

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Alexxandr [17]

Answer:

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2 years ago

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Alexandra [31]

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Please help, I will give Brainliest!!! :D​

Please help, I will give Brainliest!!! :D