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Zolol [24]
3 years ago
10

What will be the ratio of distances between the two charges of each pair of charges (1µC, 2µC) and (2µC, -3uC) so that force her

ween them is equal Use Gauss's law to derive an expression for the electric field due to an infinitely long straight wire of linear
charge density cm-1


20points!!!!!!!
​
Physics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer: Anurag Mishra - Problems in Physics - Electricity and Magnetism ... Between two infinitely long wires having linear charge densities}. and -].·there are two points A ... the ratio of the electric force between them to t:-:c grav:tadonal force between them? (a) 10 8 ... d between the first two charges on the straight line at a distance

Explanation:

MORE POWER

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When a guitar string is plucked, in what direction does the wave travel? In what directions does the string vibrate?
Alex

Answer: the waves travel in an horizontal direction while the strings vibrate in a vertical direction.

4 0
3 years ago
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Some homes that use baseboard heating use copper tubing. hot water runs through and heats the copper tubing, which in turn heats
AlekseyPX
When you heat a certain substance with a difference of temperature \Delta T the heat (energy) you must give to it is
E(=Q) =mc\Delta T
where c is the specific heat of that substance (given in J/(g*Celsius))
In this case
E=645*0.3850*(28.22-13.20) =3729.8 (Joule)

Observation: the specific heat of a substance is given in J/(g*Celsius) or J/(g*Kelvin)  because on the temperature scale a difference of 1 degree Celsius = 1 degree Kelvin
7 0
3 years ago
An electron is accelerated within a particle accelerator using a 100 MV electric potential. The 100 MeV electron moves along an
Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

Electric potential = 100 MV

Length = 4 m

Energy = 100 MeV

We need to calculate the value of \gamma

Using formula of relativistic energy

E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

Put the value into the formula

1.6\times10^{-15}= 9.1\times`10^{-31}\times9\times10^{16}(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)=\dfrac{1.6\times10^{-15}}{9.1\times10^{-31}\times9\times10^{16}}

Here, \gamma-1=(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

\gamma-1=0.01953

\gamma=0.01953+1

\gamma=1.01953

We need to calculate the length

Using formula of length

L'=\dfrac{L}{\gamma}

Put the value into the formula

L'=\dfrac{4}{1.01953}

L'=3.92\ m

Hence, The length of the tube is 3.92 m.

8 0
3 years ago
If a baseball has a zero velocity at some instant, is the acceleration of the baseball necessarily zero at that time? Explain -
ipn [44]

Answer:

No, not necessarily

Explanation:

If an object is moving with an acceleration that causes its speed to be reduced, there will be a moment in which it reaches v = 0, but this doesn't necessarily mean that the acceleration isn't acting anymore. If the object continues its movement with the same acceleration, it's velocity will become negative.

An example of an object that has zero velocity but non-zero acceleration:

If you throw an object in the air with a certain velocity, it will move vertically, reducing its velocity in a 9,8 m/s^{2} rate (which is the acceleration caused by gravity). At a certain point, the object will reach its maximum height, and will start to fall. In the exact moment that it reaches the maximum height, before it starts falling, its velocity is zero, but gravity is still acting on the object (this is the reason why it starts falling instead of just being stopped at that point). Therefore, at that point, the object has zero velocity but an acceleration of 9,8 m/s^{2}.

3 0
3 years ago
A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

diameter of the mirror d = 1.7 m

height h = 180 km = 180 × 10³ m

wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

5 0
3 years ago
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