Answer:
<h2>x = 3 and y = 4</h2>
Step-by-step explanation:
We know:
The diagonals in a parallelogram divide by halves.
Therefore KG = UG and DG = CG.
We have
KG = 5y - 8, UG = 3y, DG = 4x - 7, CG = x + 2
Substitute:
5y - 8 = 3y <em>add 8 to both sides</em>
5y = 3y + 8 <em>subtract 3y from both sides</em>
2y = 8 <em>divide both sides by 2</em>
y = 4
---------------
4x - 7 = x + 2 <em>add 7 to both sides</em>
4x = x + 9 <em>subtract x from both sides</em>
3x = 9 <em>divide both sides by 3</em>
x = 3
Answer:
Step-by-step explanation:
Use synthetic division:
The coefficients of 2x^3 - 1 are {2, 0, 0, -1}. Setting up synthetic division, we get:
1 / 2 0 0 -1
2 2 2
---------------------------
2 2 2 1
Note that the remainder is 1. The same result would be obtained through long division.
The quotient is 2x^2 + 2x + 2 with a remainder of 1.
Answer:
80 remainder 0
Step-by-step explanation:
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