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babunello [35]
2 years ago
7

Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest fo

rm. an=-2 an = an-1 -13 an=​

Mathematics
1 answer:
agasfer [191]2 years ago
6 0

From the recursive rule

a_n = a_{n-1}-13

it follows that

a_{n-1}=a_{n-2}-13 \implies a_n = a_{n-2} - 2\times13

a_{n-2}=a_{n-3}-13 \implies a_n = a_{n-3} - 3\times13

and so on. Notice how the subscript on a on the right side and the coefficient multiplied by 13 add up to n (n - 2 + 2 = n; n - 3 + 3 = n; and so on). If we continue the pattern, we'll end up with

a_n = a_1 + (n-1)\times13

so that the explicit rule for the n-th term in the sequence is

a_n = -2 + 13(n-1) \implies a_n = \boxed{13n-15}

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Step-by-step explanation:

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y = a \: cos(bx + c)  + d

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|a|

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This doesn't hold true, so we must have a phase shift

Notice that

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So if we shift this pi/2 to the right, we can get our equation to be true.

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This equation works so our equation is

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