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2 years ago

help help math math math ASAP

Mathematics

1 answer:

lakkis [162]2 years ago

8 0

It would be 2 10*2=20 20-3=17

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If a 100-pound block of ice is placed on an inclined plane that makes an angle of 35° with the horizontal, how much friction for

alexdok [17]

Answer:

F = 100(.5736)

= 57.36 lbs. (rounded off to 2 decimal places)

2) sin60 = .866

F = 18(.866)

= 15.59 lbs. (rounded off to 2 decimal places)

Step-by-step explanation:

F = friction

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3 years ago

Factor the following expression.

Natasha_Volkova [10]

Answer:

The answer is C . (5x^3-7)(2x^2+1)

Step-by-step explanation:

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3 years ago

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Norma-Jean [14]

Answer:

LMA_OO

Step-by-step explanation:

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3 years ago

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What is my answer for this question?<br> 1/3 + 1/4

Vsevolod [243]

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3 years ago

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P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

4 years ago

￼help help math math math ASAP

help help math math math ASAP