Explain in a few sentences an outline of how you would use this figure to prove that is a square.

Translate into an algebraic expression:

Ber [7]

The algebraic expression is: x% * 100

<h3>How to translate the expression?</h3>

The statement is given as:

How much x% of sugar syrup can you make if you have 100 grams of sugar?

The amount of sugar is given as:

100 grams

So, the algebraic expression is:

x% * 100

Read more about algebraic expression at:

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6 0

2 years ago

I NEED HELP ON QUESTION B AND C ASAP.

ipn [44]

Answer:

See below

Step-by-step explanation:

Assumed the dimensions of the top and bottom parts are identical.

Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:

h = 1.8 cm - 0.3 cm = 1.5 cm

Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.

V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³

<u>Total sand in the bottom part:</u>

7.96 + 4.6 = 12.56 cm³

<u>Time taken:</u>

12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds

8 0

2 years ago

What’s the correct answer

labwork [276]

There's a strong negative association between the two variables.

6 0

3 years ago

Read 2 more answers

Write a let statement, an equation, solve: Jeremy is 14 years old. This is 4 1/2 years more than half his sisters age. How old i

Art [367]

J = 14
J = 1/2S + 4 1/2

14 = 1/2S + 9/2....multiply everything by 2 to get rid of fractions
28 = S + 9
28 - 9 = S
19 = S

check...
14 = 1/2S + 9/2......S = 19
14 = 1/2(19) + 9/2
14 = 9 1/2 + 9/2
14 = 19/2+ 9/2
14 = 28/2
14 = 14 (correct)

so the sister is 19 <===

6 0

3 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0

3 years ago