<span>Left is primary
Middle is secondary
Right is tertiary
Rule look at the carbon the 'OH' functional group is attached.
If that carbon has two hydrogens then it is PRIMARY
If that carbon has one hydrogen then it is SECONDARY
If that carbon has no hydrogens then it is TERTIARY.</span>
Answer:
37.65mL
Explanation:
Given parameters:
density of liquid Z = 0.9237g/mL
Mass of liquidZ + mass of cup = 50.7g
Mass of cup= 15.92g
Volume of liquid Z in cup=?
Solution:
Density is the mass per unit volume of a substance. It is mathematically expressed as shown below:
Density =
To find the volume of liquid Z, we know the density of the liquid but we dont know the mass yet.
Mass of liquidZ = 50.7g - mass of cup = 50.7g - 15.92g = 34.98g
Therefore:
Volume of liquidZ =
=
= 37.65mL
Answer:
A Chemical equation is balanced if the reactants side of the chemical reaction has the same number total of atoms of elements as the products side of the chemical equation. While a Chemical equation is unbalanced if the reactants side of the chemical reaction has a different number total of atoms of elements as the products side of the chemical equation
Explanation:
Self explanatory
Answer:
Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M
≈0.350 M
Explanation:
From the question it is clear that,
Initial volume of sodium sulphide solution is (v₁) = 50mL
Initial concentration of sodium sulphide solution is (s₁) =0.874 M
Final volume of sodium sulphide solution is (v₂) = 250mL
Let, the final concentration of sodium sulphide solution is s₂, then according to acidimetry-alkalimetry,
v₁ × s₁ = v₂ × s₂
Or, s₂ = v₁ × s₁/v₂
= 50 × 0.874 / 250
= 0.1748 M
Therefore, concentration of 250mL sodium sulphide solution is 0.1748 M
Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M
≈0.350 M