Mass of cisplatin can be made : 144.6 g
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
K2PtCl4 (aq) + ___NH3 (aq) ___Pt(NH3)2Cl2 (s) + ___KCl (aq)
200 g of K2PtCl4
Required
mass of cisplatin Pt(NH3)2Cl2
Solution
Balanced equation
K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)
mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :
mol = mass : Mw
mol = 200 : 415
mol = 0.482
From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482
Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :
mass = mol x MW
mass = 0.482 x 300
mass = 144.6 g
Boron: isotope data. Both isotopes ofBoron, B-10 and B-11, are used extensively in the nuclear industry. B-10 is used in the form of boric acid as a chemical shim in pressurized water reactors while in the form of sodium pentaborate it is used for standby liquid control systems in boiling water reactors
The substance which is a combination of different atoms is a compound.
13.6 mol of CuCl2
you wanna use the factor label
