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muminat
2 years ago
12

Which period is older than the Triassic period? Cambrian Cretaceous Jurassic Paleogene.

Chemistry
1 answer:
scoundrel [369]2 years ago
6 0

The Triassic period is one of the geological periods and is the shortest of the Mesozoic era. Cambrian is the older era than the Triassic period.

<h3>What is Cambrian and triassic period?</h3>

The Triassic period existed 250 -200 million years ago and started after the vastest and most extreme devastation ever. It is the 1st period of the Mesozoic and is known for the movement of the Dinosaurs on the land, flying pterosaurs and swimming plesiosaurs and ichthyosaurs.

The Cambrian is the period of the Paleozoic era and is the most important period because of the appearance of many animals. In this period, the temperature raised on the planet and the ice sheets melted at a very dangerous rate leading to mass devastation.

Therefore, option A. <u>Cambrian</u> is older than the Triassic period.

Learn more about Cambrian and Triassic periods here:

brainly.com/question/11417834

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Rank the following bonds in order of decreasing bond length, based on periodic trends, starting with the longest bond at the top
sattari [20]

Answer:

H-BI,H-Se,H-S,H-I,H-Br

Explanation:

One thing that must be kept in mind is that atomic size increases down the group and decreases across the period. The bond lengths of species are influenced by the relative sizes of atoms or ions present in the bond.

The bonds in the answer have been arranged on basis of their decreasing atomic size because the greater the atomic size of the atoms, the greater the bond length and vice versa.

5 0
3 years ago
Consider the compound hydroxyapatite, Ca10(PO4)6(OH)2. Name each ion present, give the charge of each ion and show that the form
emmainna [20.7K]
Ca₁₀(PO₄)₆(OH)₂  or  Ca(OH)₂·3Ca₃(PO₄)₂

PO₄³⁻   phosphate ion
OH⁻     oxyhydroxide ion
Ca²⁺     calcium ion

10*(+2)  +  6*(-3)  +  2*(-1) = 0
 10Ca²⁺      6PO₄³⁻      2OH⁻
7 0
2 years ago
What is the molecular formula of the compound
Ipatiy [6.2K]
Molecular formula: C10H15Cl5
3 0
3 years ago
Which biome contains mostly coniferous trees and receives 35 to 100 cm of rain per year? deciduous forest taiga (boreal forest)
Sever21 [200]

option B, taiga (boreal forest).

(hope this helps ^^)

8 0
2 years ago
Read 2 more answers
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
3 years ago
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