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2 years ago

Calculate the number of atoms in a 6.29 x10^3 g sample of lithium

Chemistry

1 answer:

Over [174]2 years ago

4 0

6,290

Hope this helps!!

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Read 2 more answers

Barium phosphide Ba3P2 BaP Ba3PO4

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It A(Ba3P2)

Explanation:

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2 years ago

2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??

Zepler [3.9K]

Answer:

$d=1.78\times 10^{-7}\ Dg/\mu m^3$

Explanation:

Given,

The density of Helium is $1.78\times 10^4\ g/cm^3$

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

$d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3$

So, the density of Helium is equal to $1.78\times 10^{-7}\ Dg/\mu m^3$ .

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1 year ago