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romanna [79]
4 years ago
11

The cullinan diamond was the largest natural diamond ever found (January 25 1905 ). It weighed 3104 carat (1 carat =

Chemistry
1 answer:
bazaltina [42]4 years ago
5 0

Answer:

3.1\times 10^{25} carbon atoms are present in stone

Explanation:

Diamond is made of carbon only.

1 mg = 0.001 g

1 carat = 200 mg

So, weight of diamond in grams = (3104\times 200\times 0.001)g = 620.8 g

Molar mass of carbon = 12 g/mol

So, number of moles of carbon in diamond is the ratio of diamond to molar mass of carbon.

So, number of moles of carbon in diamond = \frac{620.8}{12}moles

1 mol of an atom = 6.023\times 10^{23} number of atoms

So, \frac{620.8}{12}moles of carbon atom = \frac{620.8}{12}\times 6.023\times 10^{23} carbon atoms = 3.1\times 10^{25} carbon atoms.

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Answer:

\boxed{\text{3.1 g}}

Explanation:

We will need an equation with masses and molar masses, so let’s gather all the information in one place.  

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\text{Moles of Ba(OH)$_{2}\cdot $8H$_{2}$O}\\= \text{ 6.5 g Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}{\text{ 315.46 g Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}

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The molar ratio is 2 mol NH₄SCN:1 mol Ba(OH)₂·8H₂O

\text{Moles of NH$_{4}$SCN} =\text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{2 mol NH$_{4}$SCN}}{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0412 mol NH$_{4}$SCN}

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\text{Mass of NH$_{4}$SCN} = \text{0.0412 mol NH$_{4}$SCN} \times \dfrac{\text{76.12 g NH$_{4}$SCN}}{\text{1 mol NH$_{4}$SCN}} =\\\textbf{3.1 g NH$_{4}$SCN}\\\\\text{You must use }\boxed{\textbf{3.1 g}}\text{ NH$_{4}$SCN}

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