Question

Type the correct answer in the box. The solubility of calcium carbonate is 14. This rate means that 14 milligrams of calcium carbonate can dissolve in 1 liter of water. How much water would be required to fully dissolve 11 grams of calcium carbonate? Express your answer to the correct number of significant figures. One milligram is equal to 0. 001 grams. It would take liters of water to fully dissolve 11 grams of calcium carbonate.

Answer 1

Ratio compares two quantities. The amount of water that will be needed to dissolve 14 grams of calcium carbonate is 1000 liters.

Given to us

The solubility of calcium carbonate is 14.

We know that to dissolve 14 milligrams of calcium carbonate we will need 1 liter of water. therefore, the ratio of water and calcium carbonate can be written as,

$\rm \dfrac{calcium\ carbonate}{water} = \dfrac{14\ milligram}{1\ liter}$

We need to find the amount of water needed to dissolve 14 grams of water, therefore, we will convert grams to milligrams,

1 gram = 1000 milligram

14 gram = 14,000 milligram

Using the same ratio,

$\rm \dfrac{14,000\ milligram}{water} = \dfrac{14\ milligram}{1\ liter}$

$\rm {water} = \dfrac{14000\ milligram \times 1\ liter}{14\ milligram}$

water = 1000 liters

Hence, the amount of water that will be needed to dissolve 14 grams of calcium carbonate is 1000 liters.

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